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Added solution for Project Euler problem 123 #3072
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Name: Prime square remainders Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2. For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25. The least value of n for which the remainder first exceeds 10^9 is 7037. Find the least value of n for which the remainder first exceeds 10^10. Reference: https://projecteuler.net/problem=123 reference: TheAlgorithms#2695
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Name: Prime square remainders Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2. For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25. The least value of n for which the remainder first exceeds 10^9 is 7037. Find the least value of n for which the remainder first exceeds 10^10. Reference: https://projecteuler.net/problem=123 reference: TheAlgorithms#2695 Co-authored-by: Ravi Kandasamy Sundaram <[email protected]>
Name: Prime square remainders Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2. For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25. The least value of n for which the remainder first exceeds 10^9 is 7037. Find the least value of n for which the remainder first exceeds 10^10. Reference: https://projecteuler.net/problem=123 reference: TheAlgorithms#2695 Co-authored-by: Ravi Kandasamy Sundaram <[email protected]>
Name: Prime square remainders Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2. For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25. The least value of n for which the remainder first exceeds 10^9 is 7037. Find the least value of n for which the remainder first exceeds 10^10. Reference: https://projecteuler.net/problem=123 reference: TheAlgorithms#2695 Co-authored-by: Ravi Kandasamy Sundaram <[email protected]>
Name: Prime square remainders Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2. For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25. The least value of n for which the remainder first exceeds 10^9 is 7037. Find the least value of n for which the remainder first exceeds 10^10. Reference: https://projecteuler.net/problem=123 reference: TheAlgorithms#2695 Co-authored-by: Ravi Kandasamy Sundaram <[email protected]>
Name: Prime square remainders
Let pn be the nth prime: 2, 3, 5, 7, 11, ..., and
let r be the remainder when (pn−1)^n + (pn+1)^n is divided by pn^2.
For example, when n = 3, p3 = 5, and 43 + 63 = 280 ≡ 5 mod 25.
The least value of n for which the remainder first exceeds 10^9 is 7037.
Find the least value of n for which the remainder first exceeds 10^10.
Reference: https://projecteuler.net/problem=123
reference: #2695
Describe your change:
Checklist:
Fixes: #{$ISSUE_NO}
.