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Minimization of while loop in Armstrong Numbers #9968
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enhancement
This PR modified some existing files
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14 tasks
My change in this code has fixed the problem you were facing, it has minimized loops and in simple way |
14 tasks
This was referenced Oct 8, 2023
Please check the pull request -> #10127 |
i would like to work on this issue it seems doable |
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Feature description
We can use math.log() to find the number of digits in a number instead of while loop.
c = log(n) + 1
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