|
| 1 | +# source - The ARRL Handbook for Radio Communications |
| 2 | + |
| 3 | +from math import exp # value of exp = 2.718281828459… |
| 4 | + |
| 5 | +""" |
| 6 | +Description |
| 7 | +----------- |
| 8 | +when a capacitor is connected with a potential source(AC or DC). It is starts to charge |
| 9 | +at a general speed but when a resistor is connected in the circuit with in series to |
| 10 | +a capacitor then the capacitor charges slowly means it will take more time than usual. |
| 11 | +while the capacitor is being charged, the voltage is in exponential function with time. |
| 12 | +
|
| 13 | +in the this function there is RC which is 'resistance(ohms)*capacitance(farads)'. |
| 14 | +also represented as τ (tau). |
| 15 | +
|
| 16 | +with the help of RC-timeconstant we can find the voltage at any time 't' from the |
| 17 | +initiation of charging a capacitor with the help of the exponential function |
| 18 | +containing RC.Both at charging and discharging of a capacitor. |
| 19 | +""" |
| 20 | + |
| 21 | + |
| 22 | +def charging_capacitor( |
| 23 | + source_voltage: float, # voltage in volts. |
| 24 | + resistance: float, # resistance in ohms. |
| 25 | + capacitance: float, # capacitance in farads. |
| 26 | + time_sec: float, # time in seconds after charging initiation of capacitor. |
| 27 | +) -> float: |
| 28 | + """ |
| 29 | + find voltage of capacitor at any nth second after the initiation of it's charging. |
| 30 | +
|
| 31 | + Parameters |
| 32 | + ---------- |
| 33 | + source_voltage : float |
| 34 | + it is going to multiply with rest of the function. |
| 35 | + resistance : float |
| 36 | + it is using in RC function. |
| 37 | + capacitance : float |
| 38 | + it is multiplying with resistance_ohms to yield output. |
| 39 | + time_sec : float |
| 40 | + it is dividing by RC.To find the voltage at nth second. |
| 41 | +
|
| 42 | + Examples |
| 43 | + -------- |
| 44 | + >>> charging_capacitor(source_voltage=15,resistance=200,capacitance=20,time_sec=2) |
| 45 | + 0.007 |
| 46 | +
|
| 47 | + >>> charging_capacitor(source_voltage=0,resistance=1000,capacitance=30,time_sec=3) |
| 48 | + Traceback (most recent call last): |
| 49 | + ... |
| 50 | + ValueError: source voltage cannot be zero. |
| 51 | +
|
| 52 | + >>> charging_capacitor(20,2000,30*pow(10,-5),4) |
| 53 | + 19.975 |
| 54 | +
|
| 55 | + >>> charging_capacitor(source_voltage=20,resistance=-2000,capacitance=30,time_sec=4) |
| 56 | + Traceback (most recent call last): |
| 57 | + ... |
| 58 | + ValueError: Resistance cannot be negative. |
| 59 | +
|
| 60 | + >>> charging_capacitor(source_voltage=-2,resistance=20,capacitance=30,time_sec=4) |
| 61 | + Traceback (most recent call last): |
| 62 | + ... |
| 63 | + ValueError: source voltage cannot be negative. |
| 64 | +
|
| 65 | + >>> charging_capacitor(source_voltage=8,resistance=0,capacitance=30,time_sec=4) |
| 66 | + Traceback (most recent call last): |
| 67 | + ... |
| 68 | + ValueError: Resistance cannot be zero. |
| 69 | +
|
| 70 | + >>> charging_capacitor(source_voltage=30,resistance=1500,capacitance=0,time_sec=4) |
| 71 | + Traceback (most recent call last): |
| 72 | + ... |
| 73 | + ValueError: Capacitance cannot be zero. |
| 74 | +
|
| 75 | + >>> charging_capacitor(source_voltage=30,resistance=23,capacitance=-40,time_sec=5) |
| 76 | + Traceback (most recent call last): |
| 77 | + ... |
| 78 | + ValueError: Capacitance cannot be negative. |
| 79 | + """ |
| 80 | + |
| 81 | + if source_voltage <= 0: |
| 82 | + if source_voltage < 0: |
| 83 | + raise ValueError("source voltage cannot be negative.") |
| 84 | + elif source_voltage == 0: |
| 85 | + raise ValueError("source voltage cannot be zero.") |
| 86 | + elif resistance <= 0: |
| 87 | + if resistance < 0: |
| 88 | + raise ValueError("Resistance cannot be negative.") |
| 89 | + elif resistance == 0: |
| 90 | + raise ValueError("Resistance cannot be zero.") |
| 91 | + elif capacitance <= 0: |
| 92 | + if capacitance < 0: |
| 93 | + raise ValueError("Capacitance cannot be negative.") |
| 94 | + elif capacitance == 0: |
| 95 | + raise ValueError("Capacitance cannot be zero.") |
| 96 | + else: |
| 97 | + return round( |
| 98 | + source_voltage * (1 - exp(-time_sec / (resistance * capacitance))), |
| 99 | + 3, |
| 100 | + ) |
| 101 | + |
| 102 | + |
| 103 | +if __name__ == "__main__": |
| 104 | + import doctest |
| 105 | + |
| 106 | + doctest.testmod() |
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