|
| 1 | +""" |
| 2 | +A Radix Tree is a data structure that represents a space-optimized |
| 3 | +trie (prefix tree) in whicheach node that is the only child is merged |
| 4 | +with its parent [https://en.wikipedia.org/wiki/Radix_tree] |
| 5 | +""" |
| 6 | + |
| 7 | + |
| 8 | +class RadixNode: |
| 9 | + def __init__(self, prefix: str = "", is_leaf: bool = False) -> None: |
| 10 | + # Mapping from the first character of the prefix of the node |
| 11 | + self.nodes: dict[str, RadixNode] = {} |
| 12 | + |
| 13 | + # A node will be a leaf if the tree contains its word |
| 14 | + self.is_leaf = is_leaf |
| 15 | + |
| 16 | + self.prefix = prefix |
| 17 | + |
| 18 | + def match(self, word: str) -> tuple[str, str, str]: |
| 19 | + """Compute the common substring of the prefix of the node and a word |
| 20 | +
|
| 21 | + Args: |
| 22 | + word (str): word to compare |
| 23 | +
|
| 24 | + Returns: |
| 25 | + (str, str, str): common substring, remaining prefix, remaining word |
| 26 | +
|
| 27 | + >>> RadixNode("myprefix").match("mystring") |
| 28 | + ('my', 'prefix', 'string') |
| 29 | + """ |
| 30 | + x = 0 |
| 31 | + for q, w in zip(self.prefix, word): |
| 32 | + if q != w: |
| 33 | + break |
| 34 | + |
| 35 | + x += 1 |
| 36 | + |
| 37 | + return self.prefix[:x], self.prefix[x:], word[x:] |
| 38 | + |
| 39 | + def insert_many(self, words: list[str]) -> None: |
| 40 | + """Insert many words in the tree |
| 41 | +
|
| 42 | + Args: |
| 43 | + words (list[str]): list of words |
| 44 | +
|
| 45 | + >>> RadixNode("myprefix").insert_many(["mystring", "hello"]) |
| 46 | + """ |
| 47 | + for word in words: |
| 48 | + self.insert(word) |
| 49 | + |
| 50 | + def insert(self, word: str) -> None: |
| 51 | + """Insert a word into the tree |
| 52 | +
|
| 53 | + Args: |
| 54 | + word (str): word to insert |
| 55 | +
|
| 56 | + >>> RadixNode("myprefix").insert("mystring") |
| 57 | + """ |
| 58 | + # Case 1: If the word is the prefix of the node |
| 59 | + # Solution: We set the current node as leaf |
| 60 | + if self.prefix == word: |
| 61 | + self.is_leaf = True |
| 62 | + |
| 63 | + # Case 2: The node has no edges that have a prefix to the word |
| 64 | + # Solution: We create an edge from the current node to a new one |
| 65 | + # containing the word |
| 66 | + elif word[0] not in self.nodes: |
| 67 | + self.nodes[word[0]] = RadixNode(prefix=word, is_leaf=True) |
| 68 | + |
| 69 | + else: |
| 70 | + incoming_node = self.nodes[word[0]] |
| 71 | + matching_string, remaining_prefix, remaining_word = incoming_node.match( |
| 72 | + word |
| 73 | + ) |
| 74 | + |
| 75 | + # Case 3: The node prefix is equal to the matching |
| 76 | + # Solution: We insert remaining word on the next node |
| 77 | + if remaining_prefix == "": |
| 78 | + self.nodes[matching_string[0]].insert(remaining_word) |
| 79 | + |
| 80 | + # Case 4: The word is greater equal to the matching |
| 81 | + # Solution: Create a node in between both nodes, change |
| 82 | + # prefixes and add the new node for the remaining word |
| 83 | + else: |
| 84 | + incoming_node.prefix = remaining_prefix |
| 85 | + |
| 86 | + aux_node = self.nodes[matching_string[0]] |
| 87 | + self.nodes[matching_string[0]] = RadixNode(matching_string, False) |
| 88 | + self.nodes[matching_string[0]].nodes[remaining_prefix[0]] = aux_node |
| 89 | + |
| 90 | + if remaining_word == "": |
| 91 | + self.nodes[matching_string[0]].is_leaf = True |
| 92 | + else: |
| 93 | + self.nodes[matching_string[0]].insert(remaining_word) |
| 94 | + |
| 95 | + def find(self, word: str) -> bool: |
| 96 | + """Returns if the word is on the tree |
| 97 | +
|
| 98 | + Args: |
| 99 | + word (str): word to check |
| 100 | +
|
| 101 | + Returns: |
| 102 | + bool: True if the word appears on the tree |
| 103 | +
|
| 104 | + >>> RadixNode("myprefix").find("mystring") |
| 105 | + False |
| 106 | + """ |
| 107 | + incoming_node = self.nodes.get(word[0], None) |
| 108 | + if not incoming_node: |
| 109 | + return False |
| 110 | + else: |
| 111 | + matching_string, remaining_prefix, remaining_word = incoming_node.match( |
| 112 | + word |
| 113 | + ) |
| 114 | + # If there is remaining prefix, the word can't be on the tree |
| 115 | + if remaining_prefix != "": |
| 116 | + return False |
| 117 | + # This applies when the word and the prefix are equal |
| 118 | + elif remaining_word == "": |
| 119 | + return incoming_node.is_leaf |
| 120 | + # We have word remaining so we check the next node |
| 121 | + else: |
| 122 | + return incoming_node.find(remaining_word) |
| 123 | + |
| 124 | + def delete(self, word: str) -> bool: |
| 125 | + """Deletes a word from the tree if it exists |
| 126 | +
|
| 127 | + Args: |
| 128 | + word (str): word to be deleted |
| 129 | +
|
| 130 | + Returns: |
| 131 | + bool: True if the word was found and deleted. False if word is not found |
| 132 | +
|
| 133 | + >>> RadixNode("myprefix").delete("mystring") |
| 134 | + False |
| 135 | + """ |
| 136 | + incoming_node = self.nodes.get(word[0], None) |
| 137 | + if not incoming_node: |
| 138 | + return False |
| 139 | + else: |
| 140 | + matching_string, remaining_prefix, remaining_word = incoming_node.match( |
| 141 | + word |
| 142 | + ) |
| 143 | + # If there is remaining prefix, the word can't be on the tree |
| 144 | + if remaining_prefix != "": |
| 145 | + return False |
| 146 | + # We have word remaining so we check the next node |
| 147 | + elif remaining_word != "": |
| 148 | + return incoming_node.delete(remaining_word) |
| 149 | + else: |
| 150 | + # If it is not a leaf, we don't have to delete |
| 151 | + if not incoming_node.is_leaf: |
| 152 | + return False |
| 153 | + else: |
| 154 | + # We delete the nodes if no edges go from it |
| 155 | + if len(incoming_node.nodes) == 0: |
| 156 | + del self.nodes[word[0]] |
| 157 | + # We merge the current node with its only child |
| 158 | + if len(self.nodes) == 1 and not self.is_leaf: |
| 159 | + merging_node = list(self.nodes.values())[0] |
| 160 | + self.is_leaf = merging_node.is_leaf |
| 161 | + self.prefix += merging_node.prefix |
| 162 | + self.nodes = merging_node.nodes |
| 163 | + # If there is more than 1 edge, we just mark it as non-leaf |
| 164 | + elif len(incoming_node.nodes) > 1: |
| 165 | + incoming_node.is_leaf = False |
| 166 | + # If there is 1 edge, we merge it with its child |
| 167 | + else: |
| 168 | + merging_node = list(incoming_node.nodes.values())[0] |
| 169 | + incoming_node.is_leaf = merging_node.is_leaf |
| 170 | + incoming_node.prefix += merging_node.prefix |
| 171 | + incoming_node.nodes = merging_node.nodes |
| 172 | + |
| 173 | + return True |
| 174 | + |
| 175 | + def print_tree(self, height: int = 0) -> None: |
| 176 | + """Print the tree |
| 177 | +
|
| 178 | + Args: |
| 179 | + height (int, optional): Height of the printed node |
| 180 | + """ |
| 181 | + if self.prefix != "": |
| 182 | + print("-" * height, self.prefix, " (leaf)" if self.is_leaf else "") |
| 183 | + |
| 184 | + for value in self.nodes.values(): |
| 185 | + value.print_tree(height + 1) |
| 186 | + |
| 187 | + |
| 188 | +def test_trie() -> bool: |
| 189 | + words = "banana bananas bandana band apple all beast".split() |
| 190 | + root = RadixNode() |
| 191 | + root.insert_many(words) |
| 192 | + |
| 193 | + assert all(root.find(word) for word in words) |
| 194 | + assert not root.find("bandanas") |
| 195 | + assert not root.find("apps") |
| 196 | + root.delete("all") |
| 197 | + assert not root.find("all") |
| 198 | + root.delete("banana") |
| 199 | + assert not root.find("banana") |
| 200 | + assert root.find("bananas") |
| 201 | + |
| 202 | + return True |
| 203 | + |
| 204 | + |
| 205 | +def pytests() -> None: |
| 206 | + assert test_trie() |
| 207 | + |
| 208 | + |
| 209 | +def main() -> None: |
| 210 | + """ |
| 211 | + >>> pytests() |
| 212 | + """ |
| 213 | + root = RadixNode() |
| 214 | + words = "banana bananas bandanas bandana band apple all beast".split() |
| 215 | + root.insert_many(words) |
| 216 | + |
| 217 | + print("Words:", words) |
| 218 | + print("Tree:") |
| 219 | + root.print_tree() |
| 220 | + |
| 221 | + |
| 222 | +if __name__ == "__main__": |
| 223 | + main() |
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