Adding the function isProthNumber(n : int) which returns true if n is a Proth number

Author: Juanitoupipou

maths/special_numbers/proth_number.py

@@ -59,6 +59,38 @@ def proth(number: int) -> int:
     return proth_list[number - 1]
 
 
+def isProthNumber(number: int) -> bool :
+    """
+    :param number: nth number to calculate in the sequence
+    :return: true if number is a Proth number, false etherwise
+    >>> proth(5)
+    true
+    >>> proth(34)
+    false
+    >>> proth(-1)
+    Traceback (most recent call last):
+        ...
+    ValueError: Input value of [number=-1] must be > 0
+    >>> proth(6.0)
+    Traceback (most recent call last):
+        ...
+    TypeError: Input value of [number=6.0] must be an integer
+    """
+    if number < 1:
+        msg = f"Input value of [number={number}] must be > 0"
+        raise ValueError(msg)
+    
+    N = number
+    N -= 1
+    n = 0
+    while N%2 == 0 :
+        N = N/2
+        n += 1
+    return N < (2**n) 
+      
+
+
+
 if __name__ == "__main__":
     import doctest
 
@@ -73,3 +105,11 @@ def proth(number: int) -> int:
             continue
 
         print(f"The {number}th Proth number: {value}")
+
+    list = [3, 5, 9, 13, 49, 57, 193, 241, 163, 201]
+
+    for number in list :
+        if isProthNumber(number):
+            print(f"{number} is a Proth number")
+        else :
+            print(f"{number} is not a Proth number")