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maths/sum_of_outcomes_for_rolling_n_sided_dice_k_time.py

@@ -1,105 +1,107 @@
 import numpy as np
 
+
 def outcome_of_rolling_n_sided_dice_k_time(n_side: int, k_time: int) -> list:
     """
-   Sum of outcomes for rolling an N-sided dice K times.
-
-   This function returns a list. The first element is an array.
-   That array contains indexes.
-   The second element is another array.
-   That array contains probabilities for getting each index values
-   as the sum of obtained side values.
-
-    Algorithm Explanation:
-
-    1. Explanation of range:
-    When we are rolling a six-sided dice the range becomes
-    1 to 6.
-    While rolling 5 times range becomes 2 to 12.
-    The sum outcomes becomes 5 when all rolling finds 1.
-    30 happens when all rolling finds 6.
-    1 is the minimum and 6 is the maximum of side values
-    for a 6 sided dice. Therefore, the range is 5 to 30.
-    Therefore, the range is k to n*k.
-
-    2. Explanation of probability distribution:
-    Say we are rolling a six-sided dice 2 times.
-    for 0 roll, the outcome is 0 with probability 1.
-    For the first roll, the outcome is 1 to 6 equally distributed.
-
-    For the second roll, each previous outcome (1-6) will face
-    an addition from the second rolling (1-6).
-    If the first outcome is (known) 3, then the probability of
-    getting each of 4 to 9 will be 1/6.
-
-    The sum becomes 2 for two 1 outcomes. But the sum becomes
-    3 for two outcomes (1,2) and (2,1).
-
-    Link:
-    https://www.thoughtco.com/
-    probabilities-of-rolling-two-dice-3126559
-    That phenomenon is the same as the convolution. However, the
-    index position is different. Therefore, we adjust the index.
-
-    NB: a) We are assuming a fair dice
-    b) Bernoulli's theory works with getting the probability of
-    exactly 3 sixes while rolling 5 times. It does not work directly
-    with the sum. The same sum can come in many combinations.
-    Finding all of those combinations and applying Bernoulli
-    is more computationally extensive.
-    c) The algorithm can be used in playing games where the sum of
-    multiple dice throwing is needed.
-
-    I used that method in my paper to draw the distribution
-    Titled: Uncertainty-aware Decisions in Cloud Computing:
-    Foundations and Future Directions
-    Journal: ACM Computing Surveys (CSUR)
-    link: https://dl.acm.org/doi/abs/10.1145/3447583
-    The PDF version of the paper is available on Google Scholar.
-
-
-    >>> import numpy as np
-    >>> outcome_of_rolling_n_sided_dice_k_time(.2,.5)
-    Traceback (most recent call last):
-        ...
-    ValueError: The function only accepts integer values
-    >>> outcome_of_rolling_n_sided_dice_k_time(-1,5)
-    Traceback (most recent call last):
-        ...
-    ValueError: Side count should be more than 1
-    >>> outcome_of_rolling_n_sided_dice_k_time(3,-2)
-    Traceback (most recent call last):
-        ...
-    ValueError: Roll count should be more than 0
-
-    >>> outcome_of_rolling_n_sided_dice_k_time(2,2)
-    ([2, 3, 4], [0.25, 0.5, 0.25])
-    >>> outcome_of_rolling_n_sided_dice_k_time(2,4)
-    ([4, 5, 6, 7, 8], [0.0625, 0.25, 0.375, 0.25, 0.0625])
-    
+    Sum of outcomes for rolling an N-sided dice K times.
+
+    This function returns a list. The first element is an array.
+    That array contains indexes.
+    The second element is another array.
+    That array contains probabilities for getting each index values
+    as the sum of obtained side values.
+
+     Algorithm Explanation:
+
+     1. Explanation of range:
+     When we are rolling a six-sided dice the range becomes
+     1 to 6.
+     While rolling 5 times range becomes 2 to 12.
+     The sum outcomes becomes 5 when all rolling finds 1.
+     30 happens when all rolling finds 6.
+     1 is the minimum and 6 is the maximum of side values
+     for a 6 sided dice. Therefore, the range is 5 to 30.
+     Therefore, the range is k to n*k.
+
+     2. Explanation of probability distribution:
+     Say we are rolling a six-sided dice 2 times.
+     for 0 roll, the outcome is 0 with probability 1.
+     For the first roll, the outcome is 1 to 6 equally distributed.
+
+     For the second roll, each previous outcome (1-6) will face
+     an addition from the second rolling (1-6).
+     If the first outcome is (known) 3, then the probability of
+     getting each of 4 to 9 will be 1/6.
+
+     The sum becomes 2 for two 1 outcomes. But the sum becomes
+     3 for two outcomes (1,2) and (2,1).
+
+     Link:
+     https://www.thoughtco.com/
+     probabilities-of-rolling-two-dice-3126559
+     That phenomenon is the same as the convolution. However, the
+     index position is different. Therefore, we adjust the index.
+
+     NB: a) We are assuming a fair dice
+     b) Bernoulli's theory works with getting the probability of
+     exactly 3 sixes while rolling 5 times. It does not work directly
+     with the sum. The same sum can come in many combinations.
+     Finding all of those combinations and applying Bernoulli
+     is more computationally extensive.
+     c) The algorithm can be used in playing games where the sum of
+     multiple dice throwing is needed.
+
+     I used that method in my paper to draw the distribution
+     Titled: Uncertainty-aware Decisions in Cloud Computing:
+     Foundations and Future Directions
+     Journal: ACM Computing Surveys (CSUR)
+     link: https://dl.acm.org/doi/abs/10.1145/3447583
+     The PDF version of the paper is available on Google Scholar.
+
+
+     >>> import numpy as np
+     >>> outcome_of_rolling_n_sided_dice_k_time(.2,.5)
+     Traceback (most recent call last):
+         ...
+     ValueError: The function only accepts integer values
+     >>> outcome_of_rolling_n_sided_dice_k_time(-1,5)
+     Traceback (most recent call last):
+         ...
+     ValueError: Side count should be more than 1
+     >>> outcome_of_rolling_n_sided_dice_k_time(3,-2)
+     Traceback (most recent call last):
+         ...
+     ValueError: Roll count should be more than 0
+
+     >>> outcome_of_rolling_n_sided_dice_k_time(2,2)
+     ([2, 3, 4], [0.25, 0.5, 0.25])
+     >>> outcome_of_rolling_n_sided_dice_k_time(2,4)
+     ([4, 5, 6, 7, 8], [0.0625, 0.25, 0.375, 0.25, 0.0625])
+
     """
 
     if n_side != int(n_side) or k_time != int(k_time):
         raise ValueError("The function only accepts integer values")
     if n_side < 2:
         raise ValueError("Side count should be more than 1")
-    if  k_time < 1:
+    if k_time < 1:
         raise ValueError("Roll count should be more than 0")
     if k_time > 100 or n_side > 100:
         raise ValueError("Limited to 100 sides or rolling to avoid memory issues")
 
     prob_dist = 1
-    dist_step = np.ones(n_side)/n_side
+    dist_step = np.ones(n_side) / n_side
 
     iter1 = 0
     while iter1 < k_time:
         prob_dist = np.convolve(prob_dist, dist_step)
-        iter1 = iter1+1
+        iter1 = iter1 + 1
 
-    index = list(range(k_time,k_time*n_side+1))
+    index = list(range(k_time, k_time * n_side + 1))
     return index, list(prob_dist)
 
-'''
+
+"""
 # Extra code for the verification
 
 index_dist = outcome_of_rolling_n_sided_dice_k_time(6, 5)
@@ -110,4 +112,4 @@ def outcome_of_rolling_n_sided_dice_k_time(n_side: int, k_time: int) -> list:
 import matplotlib.pyplot as plt
 plt.bar(index_dist[0], index_dist[1])
 
-'''
+"""