|
| 1 | +class Node: |
| 2 | + """ |
| 3 | + A class representing a node in a linked list. |
| 4 | +
|
| 5 | + Attributes: |
| 6 | + data (int): The data stored in the node. |
| 7 | + next (Node | None): A reference to the next node in the linked list. |
| 8 | +
|
| 9 | + >>> head = Node(4) |
| 10 | + >>> head.next = Node(2) |
| 11 | + >>> head.next.next = Node(1) |
| 12 | + >>> head.next.next.next = Node(3) |
| 13 | + >>> sorted_head = merge_sort_linked_list(head) |
| 14 | + >>> print_linked_list(sorted_head) |
| 15 | + 1 2 3 4 |
| 16 | + """ |
| 17 | + |
| 18 | + def __init__(self, data: int): |
| 19 | + self.data = data |
| 20 | + self.next: Node | None = None |
| 21 | + |
| 22 | + |
| 23 | +def get_middle(head: Node) -> Node: |
| 24 | + """ |
| 25 | + Find the middle node of the linked list using the slow and fast pointer technique. |
| 26 | +
|
| 27 | + Parameters: |
| 28 | + head: The head node of the linked list. |
| 29 | +
|
| 30 | + Returns: |
| 31 | + The middle node of the linked list. |
| 32 | +
|
| 33 | + Example: |
| 34 | + >>> head = Node(1) |
| 35 | + >>> head.next = Node(2) |
| 36 | + >>> head.next.next = Node(3) |
| 37 | + >>> get_middle(head).data |
| 38 | + 2 |
| 39 | + """ |
| 40 | + |
| 41 | + if head is None: |
| 42 | + return head |
| 43 | + |
| 44 | + slow = head # one node at a time |
| 45 | + fast = head # two nodes at a time |
| 46 | + while fast.next and fast.next.next: |
| 47 | + slow = slow.next |
| 48 | + fast = fast.next.next |
| 49 | + return slow |
| 50 | + |
| 51 | + |
| 52 | +def merge(left: Node | None, right: Node | None) -> Node | None: |
| 53 | + """ |
| 54 | + Merge two sorted linked lists into one sorted linked list. |
| 55 | +
|
| 56 | + Parameters: |
| 57 | + left: The head of the first sorted linked list. |
| 58 | + right: The head of the second sorted linked list. |
| 59 | +
|
| 60 | + Returns: |
| 61 | + The head of the merged sorted linked list. |
| 62 | +
|
| 63 | + Example: |
| 64 | + >>> left = Node(1) |
| 65 | + >>> left.next = Node(3) |
| 66 | + >>> right = Node(2) |
| 67 | + >>> right.next = Node(4) |
| 68 | + >>> merged = merge(left, right) |
| 69 | + >>> print_linked_list(merged) |
| 70 | + 1 2 3 4 |
| 71 | + """ |
| 72 | + |
| 73 | + if left is None: |
| 74 | + return right |
| 75 | + if right is None: |
| 76 | + return left |
| 77 | + |
| 78 | + if left.data <= right.data: |
| 79 | + result = left |
| 80 | + result.next = merge(left.next, right) |
| 81 | + else: |
| 82 | + result = right |
| 83 | + result.next = merge(left, right.next) |
| 84 | + |
| 85 | + return result |
| 86 | + |
| 87 | + |
| 88 | +def print_linked_list(head: Node | None) -> None: |
| 89 | + """ |
| 90 | + Print the linked list in a single line. |
| 91 | +
|
| 92 | + Parameters: |
| 93 | + head: The head node of the linked list. |
| 94 | +
|
| 95 | + Example: |
| 96 | + >>> head = Node(1) |
| 97 | + >>> head.next = Node(2) |
| 98 | + >>> head.next.next = Node(3) |
| 99 | + >>> print_linked_list(head) |
| 100 | + 1 2 3 |
| 101 | + """ |
| 102 | + |
| 103 | + current = head |
| 104 | + first = True # To avoid printing space before the first element |
| 105 | + while current: |
| 106 | + if not first: |
| 107 | + print(" ", end="") |
| 108 | + print(current.data, end="") |
| 109 | + first = False |
| 110 | + current = current.next |
| 111 | + print() |
| 112 | + |
| 113 | + |
| 114 | +def merge_sort_linked_list(head: Node | None) -> Node | None: |
| 115 | + """ |
| 116 | + Sort a linked list using the Merge Sort algorithm. |
| 117 | +
|
| 118 | + Parameters: |
| 119 | + head: The head node of the linked list to be sorted. |
| 120 | +
|
| 121 | + Returns: |
| 122 | + The head node of the sorted linked list. |
| 123 | +
|
| 124 | + Example: |
| 125 | + >>> head = Node(4) |
| 126 | + >>> head.next = Node(2) |
| 127 | + >>> head.next.next = Node(1) |
| 128 | + >>> head.next.next.next = Node(3) |
| 129 | + >>> sorted_head = merge_sort_linked_list(head) |
| 130 | + >>> print_linked_list(sorted_head) |
| 131 | + 1 2 3 4 |
| 132 | +
|
| 133 | + >>> head = Node(1) |
| 134 | + >>> head.next = Node(2) |
| 135 | + >>> head.next.next = Node(3) |
| 136 | + >>> head.next.next.next = Node(4) |
| 137 | + >>> sorted_head = merge_sort_linked_list(head) |
| 138 | + >>> print_linked_list(sorted_head) |
| 139 | + 1 2 3 4 |
| 140 | +
|
| 141 | + >>> head = Node(10) |
| 142 | + >>> head.next = Node(3) |
| 143 | + >>> head.next.next = Node(5) |
| 144 | + >>> head.next.next.next = Node(1) |
| 145 | + >>> sorted_head = merge_sort_linked_list(head) |
| 146 | + >>> print_linked_list(sorted_head) |
| 147 | + 1 3 5 10 |
| 148 | + """ |
| 149 | + |
| 150 | + # Base Case: 0 or 1 node |
| 151 | + if head is None or head.next is None: |
| 152 | + return head |
| 153 | + |
| 154 | + # Split the linked list into two halves |
| 155 | + middle = get_middle(head) |
| 156 | + next_to_middle = middle.next |
| 157 | + middle.next = None # Split the list into two parts |
| 158 | + |
| 159 | + left = merge_sort_linked_list(head) # Sort the left half |
| 160 | + right = merge_sort_linked_list(next_to_middle) # Sort the right half |
| 161 | + sorted_list = merge(left, right) # Merge the sorted halves |
| 162 | + return sorted_list |
| 163 | + |
| 164 | + |
| 165 | +if __name__ == "__main__": |
| 166 | + import doctest |
| 167 | + |
| 168 | + doctest.testmod() |
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