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| 1 | +#!/usr/local/bin/python3 |
| 2 | +""" |
| 3 | +Problem Description: Given two binary tree, return the merged tree. |
| 4 | +The rule for merging is that if two nodes overlap, then put the value sum of |
| 5 | +both nodes to the new value of the merged node. Otherwise, the NOT null node |
| 6 | +will be used as the node of new tree. |
| 7 | +""" |
| 8 | +from typing import Optional |
| 9 | + |
| 10 | + |
| 11 | +class Node: |
| 12 | + """ |
| 13 | + A binary node has value variable and pointers to its left and right node. |
| 14 | + """ |
| 15 | + |
| 16 | + def __init__(self, value: int = 0) -> None: |
| 17 | + self.value = value |
| 18 | + self.left: Optional[Node] = None |
| 19 | + self.right: Optional[Node] = None |
| 20 | + |
| 21 | + |
| 22 | +def merge_two_binary_trees(tree1: Optional[Node], tree2: Optional[Node]) -> Node: |
| 23 | + """ |
| 24 | + Returns root node of the merged tree. |
| 25 | +
|
| 26 | + >>> tree1 = Node(5) |
| 27 | + >>> tree1.left = Node(6) |
| 28 | + >>> tree1.right = Node(7) |
| 29 | + >>> tree1.left.left = Node(2) |
| 30 | + >>> tree2 = Node(4) |
| 31 | + >>> tree2.left = Node(5) |
| 32 | + >>> tree2.right = Node(8) |
| 33 | + >>> tree2.left.right = Node(1) |
| 34 | + >>> tree2.right.right = Node(4) |
| 35 | + >>> merged_tree = merge_two_binary_trees(tree1, tree2) |
| 36 | + >>> print_preorder(merged_tree) |
| 37 | + 9 |
| 38 | + 11 |
| 39 | + 2 |
| 40 | + 1 |
| 41 | + 15 |
| 42 | + 4 |
| 43 | + """ |
| 44 | + if tree1 is None: |
| 45 | + return tree2 |
| 46 | + if tree2 is None: |
| 47 | + return tree1 |
| 48 | + |
| 49 | + tree1.value = tree1.value + tree2.value |
| 50 | + tree1.left = merge_two_binary_trees(tree1.left, tree2.left) |
| 51 | + tree1.right = merge_two_binary_trees(tree1.right, tree2.right) |
| 52 | + return tree1 |
| 53 | + |
| 54 | + |
| 55 | +def print_preorder(root: Optional[Node]) -> None: |
| 56 | + """ |
| 57 | + Print pre-order traversal of the tree. |
| 58 | +
|
| 59 | + >>> root = Node(1) |
| 60 | + >>> root.left = Node(2) |
| 61 | + >>> root.right = Node(3) |
| 62 | + >>> print_preorder(root) |
| 63 | + 1 |
| 64 | + 2 |
| 65 | + 3 |
| 66 | + >>> print_preorder(root.right) |
| 67 | + 3 |
| 68 | + """ |
| 69 | + if root: |
| 70 | + print(root.value) |
| 71 | + print_preorder(root.left) |
| 72 | + print_preorder(root.right) |
| 73 | + |
| 74 | + |
| 75 | +if __name__ == "__main__": |
| 76 | + tree1 = Node(1) |
| 77 | + tree1.left = Node(2) |
| 78 | + tree1.right = Node(3) |
| 79 | + tree1.left.left = Node(4) |
| 80 | + |
| 81 | + tree2 = Node(2) |
| 82 | + tree2.left = Node(4) |
| 83 | + tree2.right = Node(6) |
| 84 | + tree2.left.right = Node(9) |
| 85 | + tree2.right.right = Node(5) |
| 86 | + |
| 87 | + print("Tree1 is: ") |
| 88 | + print_preorder(tree1) |
| 89 | + print("Tree2 is: ") |
| 90 | + print_preorder(tree2) |
| 91 | + merged_tree = merge_two_binary_trees(tree1, tree2) |
| 92 | + print("Merged Tree is: ") |
| 93 | + print_preorder(merged_tree) |
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