Update WaterJugProblem.js

prettier

Author: swappy-2003

Diff for: Recursive/WaterJugProblem.js

@@ -1,43 +1,53 @@
 // WaterJugProblem.js
 
 export function canMeasureWater(jug1Capacity, jug2Capacity, targetAmount) {
-    // Input validation
-    if (jug1Capacity < 0 || jug2Capacity < 0) {
-        throw new Error('Invalid input: capacities must be non-negative.');
-    }
-    if (targetAmount < 0) {
-        throw new Error('Invalid input: target amount must be non-negative.');
-    }
-
-    // Base case: If the target amount is greater than the sum of both jugs, it's not possible.
-    if (targetAmount > jug1Capacity + jug2Capacity) return false;
-
-    // Use BFS to explore possible states.
-    let visited = new Set(); // To keep track of visited states.
-    let queue = [[0, 0]]; // Starting with both jugs empty.
-
-    while (queue.length > 0) {
-        let [jug1, jug2] = queue.shift();
-
-        // If we've reached the target amount in either jug.
-        if (jug1 === targetAmount || jug2 === targetAmount || jug1 + jug2 === targetAmount) {
-            return true;
-        }
-
-        // If this state has been visited, skip it.
-        let state = `${jug1},${jug2}`;
-        if (visited.has(state)) continue;
-        visited.add(state);
-
-        // Add all possible next states to the queue:
-        queue.push([jug1Capacity, jug2]); // Fill Jug 1
-        queue.push([jug1, jug2Capacity]); // Fill Jug 2
-        queue.push([0, jug2]); // Empty Jug 1
-        queue.push([jug1, 0]); // Empty Jug 2
-        queue.push([Math.max(0, jug1 - (jug2Capacity - jug2)), Math.min(jug2Capacity, jug1 + jug2)]); // Pour Jug 1 into Jug 2
-        queue.push([Math.min(jug1Capacity, jug1 + jug2), Math.max(0, jug2 - (jug1Capacity - jug1))]); // Pour Jug 2 into Jug 1
+  // Input validation
+  if (jug1Capacity < 0 || jug2Capacity < 0) {
+    throw new Error("Invalid input: capacities must be non-negative.");
+  }
+  if (targetAmount < 0) {
+    throw new Error("Invalid input: target amount must be non-negative.");
+  }
+
+  // Base case: If the target amount is greater than the sum of both jugs, it's not possible.
+  if (targetAmount > jug1Capacity + jug2Capacity) return false;
+
+  // Use BFS to explore possible states.
+  let visited = new Set(); // To keep track of visited states.
+  let queue = [[0, 0]]; // Starting with both jugs empty.
+
+  while (queue.length > 0) {
+    let [jug1, jug2] = queue.shift();
+
+    // If we've reached the target amount in either jug.
+    if (
+      jug1 === targetAmount ||
+      jug2 === targetAmount ||
+      jug1 + jug2 === targetAmount
+    ) {
+      return true;
     }
 
-    // If no solution is found
-    return false;
+    // If this state has been visited, skip it.
+    let state = `${jug1},${jug2}`;
+    if (visited.has(state)) continue;
+    visited.add(state);
+
+    // Add all possible next states to the queue:
+    queue.push([jug1Capacity, jug2]); // Fill Jug 1
+    queue.push([jug1, jug2Capacity]); // Fill Jug 2
+    queue.push([0, jug2]); // Empty Jug 1
+    queue.push([jug1, 0]); // Empty Jug 2
+    queue.push([
+      Math.max(0, jug1 - (jug2Capacity - jug2)),
+      Math.min(jug2Capacity, jug1 + jug2),
+    ]); // Pour Jug 1 into Jug 2
+    queue.push([
+      Math.min(jug1Capacity, jug1 + jug2),
+      Math.max(0, jug2 - (jug1Capacity - jug1)),
+    ]); // Pour Jug 2 into Jug 1
+  }
+
+  // If no solution is found
+  return false;
 }