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1 | 1 | package com.thealgorithms.conversions;
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2 | 2 |
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3 |
| -// Hex [0-9],[A-F] -> Binary [0,1] |
| 3 | +/** |
| 4 | + * Utility class for converting hexadecimal numbers to binary representation. |
| 5 | + * <p> |
| 6 | + * A hexadecimal number consists of digits from {@code [0-9]} and {@code [A-F]} (case-insensitive), |
| 7 | + * while binary representation uses only {@code [0, 1]}. |
| 8 | + * <p> |
| 9 | + * This class provides methods to: |
| 10 | + * <ul> |
| 11 | + * <li>Convert a hexadecimal string to its binary string equivalent.</li> |
| 12 | + * <li>Ensure the binary output is padded to 8 bits (1 byte).</li> |
| 13 | + * </ul> |
| 14 | + * <p> |
| 15 | + * Example: |
| 16 | + * <ul> |
| 17 | + * <li>{@code "A1"} → {@code "10100001"}</li> |
| 18 | + * <li>{@code "1"} → {@code "00000001"}</li> |
| 19 | + * </ul> |
| 20 | + * |
| 21 | + * <p>This class assumes that the input hexadecimal string is valid.</p> |
| 22 | + */ |
4 | 23 | public class HexaDecimalToBinary {
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| 24 | + |
| 25 | + /** |
| 26 | + * Converts a hexadecimal string to its binary string equivalent. |
| 27 | + * The binary output is padded to a minimum of 8 bits (1 byte). |
| 28 | + * Steps: |
| 29 | + * <ol> |
| 30 | + * <li>Convert the hexadecimal string to an integer.</li> |
| 31 | + * <li>Convert the integer to a binary string.</li> |
| 32 | + * <li>Pad the binary string to ensure it is at least 8 bits long.</li> |
| 33 | + * <li>Return the padded binary string.</li> |
| 34 | + * </ol> |
| 35 | + * |
| 36 | + * @param numHex the hexadecimal string (e.g., "A1", "7F") |
| 37 | + * @throws NumberFormatException if the input string is not a valid hexadecimal number |
| 38 | + * @return the binary string representation, padded to 8 bits (e.g., "10100001") |
| 39 | + */ |
5 | 40 | public String convert(String numHex) {
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6 |
| - // String a HexaDecimal: |
7 | 41 | int conHex = Integer.parseInt(numHex, 16);
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8 |
| - // Hex a Binary: |
9 | 42 | String binary = Integer.toBinaryString(conHex);
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10 |
| - // Output: |
11 | 43 | return completeDigits(binary);
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12 | 44 | }
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13 | 45 |
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| 46 | + /** |
| 47 | + * Pads the binary string to ensure it is at least 8 bits long. |
| 48 | + * If the binary string is shorter than 8 bits, it adds leading zeros. |
| 49 | + * |
| 50 | + * @param binNum the binary string to pad |
| 51 | + * @return the padded binary string with a minimum length of 8 |
| 52 | + */ |
14 | 53 | public String completeDigits(String binNum) {
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15 |
| - final int longBits = 8; |
16 |
| - for (int i = binNum.length(); i < longBits; i++) { |
| 54 | + final int byteSize = 8; |
| 55 | + while (binNum.length() < byteSize) { |
17 | 56 | binNum = "0" + binNum;
|
18 | 57 | }
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19 | 58 | return binNum;
|
20 | 59 | }
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21 |
| - |
22 |
| - public static void main(String[] args) { |
23 |
| - // Testing Numbers: |
24 |
| - String[] hexNums = { |
25 |
| - "1", |
26 |
| - "A1", |
27 |
| - "ef", |
28 |
| - "BA", |
29 |
| - "AA", |
30 |
| - "BB", |
31 |
| - "19", |
32 |
| - "01", |
33 |
| - "02", |
34 |
| - "03", |
35 |
| - "04", |
36 |
| - }; |
37 |
| - HexaDecimalToBinary objConvert = new HexaDecimalToBinary(); |
38 |
| - |
39 |
| - for (String num : hexNums) { |
40 |
| - System.out.println(num + " = " + objConvert.convert(num)); |
41 |
| - } |
42 |
| - } |
43 | 60 | }
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