refactor: LongestNonRepetitiveSubstring

Author: alxkm

src/main/java/com/thealgorithms/strings/LongestNonRepetitiveSubstring.java

@@ -3,47 +3,40 @@
 import java.util.HashMap;
 import java.util.Map;
 
+/**
+ * Class for finding the length of the longest substring without repeating characters.
+ */
 final class LongestNonRepetitiveSubstring {
     private LongestNonRepetitiveSubstring() {
     }
 
+    /**
+     * Finds the length of the longest substring without repeating characters.
+     *
+     * @param s the input string
+     * @return the length of the longest non-repetitive substring
+     */
     public static int lengthOfLongestSubstring(String s) {
-        int max = 0;
+        int maxLength = 0;
         int start = 0;
-        int i = 0;
-        Map<Character, Integer> map = new HashMap<>();
-
-        while (i < s.length()) {
-            char temp = s.charAt(i);
-
-            // adding key to map if not present
-            if (!map.containsKey(temp)) {
-                map.put(temp, 0);
-            } else if (s.charAt(start) == temp) {
-                start++;
-            } else if (s.charAt(i - 1) == temp) {
-                if (max < map.size()) {
-                    max = map.size();
-                }
-                map = new HashMap<>();
-                start = i;
-                i--;
-            } else {
-                if (max < map.size()) {
-                    max = map.size();
-                }
-                while (s.charAt(start) != temp) {
-                    map.remove(s.charAt(start));
-                    start++;
-                }
-                start++;
+        Map<Character, Integer> charIndexMap = new HashMap<>();
+
+        for (int i = 0; i < s.length(); i++) {
+            char currentChar = s.charAt(i);
+
+            // If the character is already in the map and its index is within the current window
+            if (charIndexMap.containsKey(currentChar) && charIndexMap.get(currentChar) >= start) {
+                // Move the start to the position right after the last occurrence of the current character
+                start = charIndexMap.get(currentChar) + 1;
             }
 
-            i++;
-        }
-        if (max < map.size()) {
-            max = map.size();
+            // Update the last seen index of the current character
+            charIndexMap.put(currentChar, i);
+
+            // Calculate the maximum length of the substring without repeating characters
+            maxLength = Math.max(maxLength, i - start + 1);
         }
-        return max;
+
+        return maxLength;
     }
 }

src/test/java/com/thealgorithms/strings/LongestNonRepetitiveSubstringTest.java

@@ -1,15 +1,22 @@
 package com.thealgorithms.strings;
 
-import org.junit.jupiter.api.Assertions;
-import org.junit.jupiter.api.Test;
+import static org.junit.jupiter.api.Assertions.assertEquals;
+
+import java.util.stream.Stream;
+import org.junit.jupiter.params.ParameterizedTest;
+import org.junit.jupiter.params.provider.Arguments;
+import org.junit.jupiter.params.provider.MethodSource;
 
 public class LongestNonRepetitiveSubstringTest {
 
-    @Test
-    public void palindrome() {
-        String input1 = "HelloWorld";
-        String input2 = "javaIsAProgrammingLanguage";
-        Assertions.assertEquals(LongestNonRepetitiveSubstring.lengthOfLongestSubstring(input1), 5);
-        Assertions.assertEquals(LongestNonRepetitiveSubstring.lengthOfLongestSubstring(input2), 9);
+    private static Stream<Arguments> provideTestCases() {
+        return Stream.of(Arguments.of("", 0), Arguments.of("a", 1), Arguments.of("abcde", 5), Arguments.of("aaaaa", 1), Arguments.of("abca", 3), Arguments.of("abcdeabc", 5),
+                Arguments.of("a1b2c3", 6), Arguments.of("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890", 62), Arguments.of("aabb", 2), Arguments.of("abcdefghijabc", 10));
+    }
+
+    @ParameterizedTest
+    @MethodSource("provideTestCases")
+    void testLengthOfLongestSubstring(String input, int expectedLength) {
+        assertEquals(expectedLength, LongestNonRepetitiveSubstring.lengthOfLongestSubstring(input));
     }
 }