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DIRECTORY.md

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pom.xml

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<dependency>
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<groupId>org.junit</groupId>
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<artifactId>junit-bom</artifactId>
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<version>5.11.2</version>
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<version>5.11.3</version>
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<type>pom</type>
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<scope>import</scope>
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</dependency>
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<dependency>
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<groupId>org.junit.jupiter</groupId>
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<artifactId>junit-jupiter</artifactId>
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<version>5.11.2</version>
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<version>5.11.3</version>
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<scope>test</scope>
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</dependency>
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<dependency>
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<dependency>
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<groupId>org.mockito</groupId>
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<artifactId>mockito-core</artifactId>
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<version>5.14.1</version>
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<version>5.14.2</version>
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<scope>test</scope>
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</dependency>
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<dependency>
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<groupId>org.junit.jupiter</groupId>
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<artifactId>junit-jupiter-api</artifactId>
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<version>5.11.2</version>
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<version>5.11.3</version>
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<scope>test</scope>
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</dependency>
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<dependency>
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<plugin>
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<groupId>com.github.spotbugs</groupId>
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<artifactId>spotbugs-maven-plugin</artifactId>
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<version>4.8.6.4</version>
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<version>4.8.6.5</version>
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<configuration>
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<excludeFilterFile>spotbugs-exclude.xml</excludeFilterFile>
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<includeTests>true</includeTests>

src/main/java/com/thealgorithms/bitmanipulation/IsPowerTwo.java

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package com.thealgorithms.bitmanipulation;
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/**
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* Is number power of 2
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* Utility class for checking if a number is a power of two.
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* A power of two is a number that can be expressed as 2^n where n is a non-negative integer.
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* This class provides a method to determine if a given integer is a power of two using bit manipulation.
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*
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* @author Bama Charan Chhandogi (https://github.com/BamaCharanChhandogi)
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*/
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public final class IsPowerTwo {
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private IsPowerTwo() {
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}
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/**
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* Checks if the given integer is a power of two.
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*
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* A number is considered a power of two if it is greater than zero and
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* has exactly one '1' bit in its binary representation. This method
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* uses the property that for any power of two (n), the expression
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* (n & (n - 1)) will be zero.
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*
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* @param number the integer to check
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* @return true if the number is a power of two, false otherwise
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*/
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public static boolean isPowerTwo(int number) {
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if (number <= 0) {
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return false;

src/main/java/com/thealgorithms/bitmanipulation/NonRepeatingNumberFinder.java

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package com.thealgorithms.bitmanipulation;
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/**
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* Find Non Repeating Number
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* A utility class to find the non-repeating number in an array where every other number repeats.
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* This class contains a method to identify the single unique number using bit manipulation.
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*
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* The solution leverages the properties of the XOR operation, which states that:
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* - x ^ x = 0 for any integer x (a number XORed with itself is zero)
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* - x ^ 0 = x for any integer x (a number XORed with zero is the number itself)
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*
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* Using these properties, we can find the non-repeating number in linear time with constant space.
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*
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* Example:
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* Given the input array [2, 3, 5, 2, 3], the output will be 5 since it does not repeat.
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*
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* @author Bama Charan Chhandogi (https://github.com/BamaCharanChhandogi)
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*/
7-
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public final class NonRepeatingNumberFinder {
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private NonRepeatingNumberFinder() {
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}
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22+
/**
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* Finds the non-repeating number in the given array.
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*
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* @param arr an array of integers where every number except one appears twice
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* @return the integer that appears only once in the array or 0 if the array is empty
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*/
1228
public static int findNonRepeatingNumber(int[] arr) {
1329
int result = 0;
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for (int num : arr) {
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package com.thealgorithms.bitmanipulation;
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/**
4-
* Find the Number Appearing Odd Times in an array
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* This class provides a method to find the element that appears an
5+
* odd number of times in an array. All other elements in the array
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* must appear an even number of times for the logic to work.
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*
8+
* The solution uses the XOR operation, which has the following properties:
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* - a ^ a = 0 (XOR-ing the same numbers cancels them out)
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* - a ^ 0 = a
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* - XOR is commutative and associative.
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*
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* Time Complexity: O(n), where n is the size of the array.
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* Space Complexity: O(1), as no extra space is used.
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*
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* Usage Example:
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* int result = NumberAppearingOddTimes.findOddOccurrence(new int[]{1, 2, 1, 2, 3});
18+
* // result will be 3
19+
*
520
* @author Lakshyajeet Singh Goyal (https://github.com/DarkMatter-999)
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*/
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823
public final class NumberAppearingOddTimes {
924
private NumberAppearingOddTimes() {
1025
}
26+
27+
/**
28+
* Finds the element in the array that appears an odd number of times.
29+
*
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* @param arr the input array containing integers, where all elements
31+
* except one appear an even number of times.
32+
* @return the integer that appears an odd number of times.
33+
*/
1134
public static int findOddOccurrence(int[] arr) {
1235
int result = 0;
13-
14-
// XOR all elements in the array
1536
for (int num : arr) {
1637
result ^= num;
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}
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return result;
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}
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}
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package com.thealgorithms.ciphers;
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3+
import java.util.HashMap;
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import java.util.Map;
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6+
/**
7+
* The Baconian Cipher is a substitution cipher where each letter is represented
8+
* by a group of five binary digits (A's and B's). It can also be used to hide
9+
* messages within other texts, making it a simple form of steganography.
10+
* https://en.wikipedia.org/wiki/Bacon%27s_cipher
11+
*
12+
* @author Bennybebo
13+
*/
14+
public class BaconianCipher {
15+
16+
private static final Map<Character, String> BACONIAN_MAP = new HashMap<>();
17+
private static final Map<String, Character> REVERSE_BACONIAN_MAP = new HashMap<>();
18+
19+
static {
20+
// Initialize the Baconian cipher mappings
21+
String[] baconianAlphabet = {"AAAAA", "AAAAB", "AAABA", "AAABB", "AABAA", "AABAB", "AABBA", "AABBB", "ABAAA", "ABAAB", "ABABA", "ABABB", "ABBAA", "ABBAB", "ABBBA", "ABBBB", "BAAAA", "BAAAB", "BAABA", "BAABB", "BABAA", "BABAB", "BABBA", "BABBB", "BBAAA", "BBAAB"};
22+
char letter = 'A';
23+
for (String code : baconianAlphabet) {
24+
BACONIAN_MAP.put(letter, code);
25+
REVERSE_BACONIAN_MAP.put(code, letter);
26+
letter++;
27+
}
28+
29+
// Handle I/J as the same letter
30+
BACONIAN_MAP.put('I', BACONIAN_MAP.get('J'));
31+
REVERSE_BACONIAN_MAP.put(BACONIAN_MAP.get('I'), 'I');
32+
}
33+
34+
/**
35+
* Encrypts the given plaintext using the Baconian cipher.
36+
*
37+
* @param plaintext The plaintext message to encrypt.
38+
* @return The ciphertext as a binary (A/B) sequence.
39+
*/
40+
public String encrypt(String plaintext) {
41+
StringBuilder ciphertext = new StringBuilder();
42+
plaintext = plaintext.toUpperCase().replaceAll("[^A-Z]", ""); // Remove non-letter characters
43+
44+
for (char letter : plaintext.toCharArray()) {
45+
ciphertext.append(BACONIAN_MAP.get(letter));
46+
}
47+
48+
return ciphertext.toString();
49+
}
50+
51+
/**
52+
* Decrypts the given ciphertext encoded in binary (A/B) format using the Baconian cipher.
53+
*
54+
* @param ciphertext The ciphertext to decrypt.
55+
* @return The decrypted plaintext message.
56+
*/
57+
public String decrypt(String ciphertext) {
58+
StringBuilder plaintext = new StringBuilder();
59+
60+
for (int i = 0; i < ciphertext.length(); i += 5) {
61+
String code = ciphertext.substring(i, i + 5);
62+
if (REVERSE_BACONIAN_MAP.containsKey(code)) {
63+
plaintext.append(REVERSE_BACONIAN_MAP.get(code));
64+
} else {
65+
throw new IllegalArgumentException("Invalid Baconian code: " + code);
66+
}
67+
}
68+
69+
return plaintext.toString();
70+
}
71+
}
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package com.thealgorithms.ciphers;
2+
3+
import java.math.BigInteger;
4+
5+
public final class DiffieHellman {
6+
7+
private final BigInteger base;
8+
private final BigInteger secret;
9+
private final BigInteger prime;
10+
11+
// Constructor to initialize base, secret, and prime
12+
public DiffieHellman(BigInteger base, BigInteger secret, BigInteger prime) {
13+
// Check for non-null and positive values
14+
if (base == null || secret == null || prime == null || base.signum() <= 0 || secret.signum() <= 0 || prime.signum() <= 0) {
15+
throw new IllegalArgumentException("Base, secret, and prime must be non-null and positive values.");
16+
}
17+
this.base = base;
18+
this.secret = secret;
19+
this.prime = prime;
20+
}
21+
22+
// Method to calculate public value (g^x mod p)
23+
public BigInteger calculatePublicValue() {
24+
// Returns g^x mod p
25+
return base.modPow(secret, prime);
26+
}
27+
28+
// Method to calculate the shared secret key (otherPublic^secret mod p)
29+
public BigInteger calculateSharedSecret(BigInteger otherPublicValue) {
30+
if (otherPublicValue == null || otherPublicValue.signum() <= 0) {
31+
throw new IllegalArgumentException("Other public value must be non-null and positive.");
32+
}
33+
// Returns b^x mod p or a^y mod p
34+
return otherPublicValue.modPow(secret, prime);
35+
}
36+
}
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1+
package com.thealgorithms.ciphers;
2+
3+
public final class MonoAlphabetic {
4+
5+
private MonoAlphabetic() {
6+
throw new UnsupportedOperationException("Utility class");
7+
}
8+
9+
// Encryption method
10+
public static String encrypt(String data, String key) {
11+
if (!data.matches("[A-Z]+")) {
12+
throw new IllegalArgumentException("Input data contains invalid characters. Only uppercase A-Z are allowed.");
13+
}
14+
StringBuilder sb = new StringBuilder();
15+
16+
// Encrypt each character
17+
for (char c : data.toCharArray()) {
18+
int idx = charToPos(c); // Get the index of the character
19+
sb.append(key.charAt(idx)); // Map to the corresponding character in the key
20+
}
21+
return sb.toString();
22+
}
23+
24+
// Decryption method
25+
public static String decrypt(String data, String key) {
26+
StringBuilder sb = new StringBuilder();
27+
28+
// Decrypt each character
29+
for (char c : data.toCharArray()) {
30+
int idx = key.indexOf(c); // Find the index of the character in the key
31+
if (idx == -1) {
32+
throw new IllegalArgumentException("Input data contains invalid characters.");
33+
}
34+
sb.append(posToChar(idx)); // Convert the index back to the original character
35+
}
36+
return sb.toString();
37+
}
38+
39+
// Helper method: Convert a character to its position in the alphabet
40+
private static int charToPos(char c) {
41+
return c - 'A'; // Subtract 'A' to get position (0 for A, 1 for B, etc.)
42+
}
43+
44+
// Helper method: Convert a position in the alphabet to a character
45+
private static char posToChar(int pos) {
46+
return (char) (pos + 'A'); // Add 'A' to convert position back to character
47+
}
48+
}

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