Merge branch 'master' into add_test_tower_hanoi

Author: lorduke22

DIRECTORY.md

@@ -1,56 +1,80 @@
 package com.thealgorithms.bitmanipulation;
 
 /**
- * This class provides methods to convert between BCD (Binary-Coded Decimal) and binary.
+ * This class provides methods to convert between BCD (Binary-Coded Decimal) and decimal numbers.
  *
- * Binary-Coded Decimal (BCD) is a class of binary encodings of decimal numbers where each decimal digit is represented by a fixed number of binary digits, usually four or eight.
+ * BCD is a class of binary encodings of decimal numbers where each decimal digit is represented by a fixed number of binary digits, usually four or eight.
  *
  * For more information, refer to the
  * <a href="https://en.wikipedia.org/wiki/Binary-coded_decimal">Binary-Coded Decimal</a> Wikipedia page.
  *
  * <b>Example usage:</b>
  * <pre>
- * int binary = BcdConversion.bcdToBinary(0x1234);
- * System.out.println("BCD 0x1234 to binary: " + binary); // Output: 1234
+ * int decimal = BcdConversion.bcdToDecimal(0x1234);
+ * System.out.println("BCD 0x1234 to decimal: " + decimal); // Output: 1234
  *
- * int bcd = BcdConversion.binaryToBcd(1234);
- * System.out.println("Binary 1234 to BCD: " + Integer.toHexString(bcd)); // Output: 0x1234
+ * int bcd = BcdConversion.decimalToBcd(1234);
+ * System.out.println("Decimal 1234 to BCD: " + Integer.toHexString(bcd)); // Output: 0x1234
  * </pre>
  */
 public final class BcdConversion {
     private BcdConversion() {
     }
+
     /**
-     * Converts a BCD (Binary-Coded Decimal) number to binary.
+     * Converts a BCD (Binary-Coded Decimal) number to a decimal number.
+     * <p>Steps:
+     * <p>1. Validate the BCD number to ensure all digits are between 0 and 9.
+     * <p>2. Extract the last 4 bits (one BCD digit) from the BCD number.
+     * <p>3. Multiply the extracted digit by the corresponding power of 10 and add it to the decimal number.
+     * <p>4. Shift the BCD number right by 4 bits to process the next BCD digit.
+     * <p>5. Repeat steps 1-4 until the BCD number is zero.
      *
      * @param bcd The BCD number.
-     * @return The corresponding binary number.
+     * @return The corresponding decimal number.
+     * @throws IllegalArgumentException if the BCD number contains invalid digits.
      */
-    public static int bcdToBinary(int bcd) {
-        int binary = 0;
+    public static int bcdToDecimal(int bcd) {
+        int decimal = 0;
         int multiplier = 1;
+
+        // Validate BCD digits
         while (bcd > 0) {
-            int digit = bcd & 0xF; // Extract the last 4 bits (one BCD digit)
-            binary += digit * multiplier;
+            int digit = bcd & 0xF;
+            if (digit > 9) {
+                throw new IllegalArgumentException("Invalid BCD digit: " + digit);
+            }
+            decimal += digit * multiplier;
             multiplier *= 10;
-            bcd >>= 4; // Shift right by 4 bits to process the next BCD digit
+            bcd >>= 4;
         }
-        return binary;
+        return decimal;
     }
 
     /**
-     * Converts a binary number to BCD (Binary-Coded Decimal).
+     * Converts a decimal number to BCD (Binary-Coded Decimal).
+     * <p>Steps:
+     * <p>1. Check if the decimal number is within the valid range for BCD (0 to 9999).
+     * <p>2. Extract the last decimal digit from the decimal number.
+     * <p>3. Shift the digit to the correct BCD position and add it to the BCD number.
+     * <p>4. Remove the last decimal digit from the decimal number.
+     * <p>5. Repeat steps 2-4 until the decimal number is zero.
      *
-     * @param binary The binary number.
+     * @param decimal The decimal number.
      * @return The corresponding BCD number.
+     * @throws IllegalArgumentException if the decimal number is greater than 9999.
      */
-    public static int binaryToBcd(int binary) {
+    public static int decimalToBcd(int decimal) {
+        if (decimal < 0 || decimal > 9999) {
+            throw new IllegalArgumentException("Value out of bounds for BCD representation: " + decimal);
+        }
+
         int bcd = 0;
         int shift = 0;
-        while (binary > 0) {
-            int digit = binary % 10; // Extract the last decimal digit
-            bcd |= (digit << (shift * 4)); // Shift the digit to the correct BCD position
-            binary /= 10; // Remove the last decimal digit
+        while (decimal > 0) {
+            int digit = decimal % 10;
+            bcd |= (digit << (shift * 4));
+            decimal /= 10;
             shift++;
         }
         return bcd;

src/main/java/com/thealgorithms/bitmanipulation/BcdConversion.java

@@ -0,0 +1,58 @@
+package com.thealgorithms.conversions;
+
+/**
+ * Converts an IPv4 address to its binary equivalent and vice-versa.
+ * IP to Binary: Converts an IPv4 address to its binary equivalent.
+ * Example: 127.3.4.5 -> 01111111.00000011.00000100.00000101
+ *
+ * Binary to IP: Converts a binary equivalent to an IPv4 address.
+ * Example: 01111111.00000011.00000100.00000101 -> 127.3.4.5
+ *
+ * @author Hardvan
+ */
+public final class IPConverter {
+    private IPConverter() {
+    }
+
+    /**
+     * Converts an IPv4 address to its binary equivalent.
+     * @param ip The IPv4 address to convert.
+     * @return The binary equivalent of the IPv4 address.
+     */
+    public static String ipToBinary(String ip) {
+        StringBuilder binary = new StringBuilder();
+        for (String octet : ip.split("\\.")) {
+            binary.append(octetToBinary(Integer.parseInt(octet))).append(".");
+        }
+        return binary.substring(0, binary.length() - 1);
+    }
+
+    /**
+     * Converts a single octet to its 8-bit binary representation.
+     * @param octet The octet to convert (0-255).
+     * @return The 8-bit binary representation as a String.
+     */
+    private static String octetToBinary(int octet) {
+        char[] binary = {'0', '0', '0', '0', '0', '0', '0', '0'};
+        for (int i = 7; i >= 0; i--) {
+            if ((octet & 1) == 1) {
+                binary[i] = '1';
+            }
+            octet >>>= 1;
+        }
+        return new String(binary);
+    }
+
+    /**
+     * Converts a binary equivalent to an IPv4 address.
+     * @param binary The binary equivalent to convert.
+     * @return The IPv4 address of the binary equivalent.
+     */
+    public static String binaryToIP(String binary) {
+        StringBuilder ip = new StringBuilder();
+        for (String octet : binary.split("\\.")) {
+            ip.append(Integer.parseInt(octet, 2)).append(".");
+        }
+        return ip.substring(0, ip.length() - 1);
+    }
+}

src/main/java/com/thealgorithms/conversions/IPConverter.java

@@ -1,29 +1,65 @@
 package com.thealgorithms.others;
 
-import java.util.Scanner;
+import java.util.List;
 
+/**
+ * The {@code TowerOfHanoi} class provides a recursive solution to the Tower of Hanoi puzzle.
+ * This puzzle involves moving a set of discs from one pole to another, following specific rules:
+ * 1. Only one disc can be moved at a time.
+ * 2. A disc can only be placed on top of a larger disc.
+ * 3. All discs must start on one pole and end on another.
+ *
+ * This implementation recursively calculates the steps required to solve the puzzle and stores them
+ * in a provided list.
+ *
+ * <p>
+ * For more information about the Tower of Hanoi, see
+ * <a href="https://en.wikipedia.org/wiki/Tower_of_Hanoi">Tower of Hanoi on Wikipedia</a>.
+ * </p>
+ *
+ * The {@code shift} method takes the number of discs and the names of the poles,
+ * and appends the steps required to solve the puzzle to the provided list.
+ * Time Complexity: O(2^n) - Exponential time complexity due to the recursive nature of the problem.
+ * Space Complexity: O(n) - Linear space complexity due to the recursion stack.
+ * Wikipedia: https://en.wikipedia.org/wiki/Tower_of_Hanoi
+ */
 final class TowerOfHanoi {
+
     private TowerOfHanoi() {
     }
 
-    public static void shift(int n, String startPole, String intermediatePole, String endPole) {
-        // if n becomes zero the program returns thus ending the loop.
+    /**
+     * Recursively solve the Tower of Hanoi puzzle by moving discs between poles.
+     *
+     * @param n                The number of discs to move.
+     * @param startPole        The name of the start pole from which discs are moved.
+     * @param intermediatePole The name of the intermediate pole used as a temporary holding area.
+     * @param endPole          The name of the end pole to which discs are moved.
+     * @param result           A list to store the steps required to solve the puzzle.
+     *
+     *                         <p>
+     *                         This method is called recursively to move n-1 discs
+     *                         to the intermediate pole,
+     *                         then moves the nth disc to the end pole, and finally
+     *                         moves the n-1 discs from the
+     *                         intermediate pole to the end pole.
+     *                         </p>
+     *
+     *                         <p>
+     *                         Time Complexity: O(2^n) - Exponential time complexity due to the recursive nature of the problem.
+     *                         Space Complexity: O(n) - Linear space complexity due to the recursion stack.
+     *                         </p>
+     */
+    public static void shift(int n, String startPole, String intermediatePole, String endPole, List<String> result) {
         if (n != 0) {
-            // Shift function is called in recursion for swapping the n-1 disc from the startPole to
-            // the intermediatePole
-            shift(n - 1, startPole, endPole, intermediatePole);
-            System.out.format("Move %d from %s to %s%n", n, startPole, endPole); // Result Printing
-            // Shift function is called in recursion for swapping the n-1 disc from the
-            // intermediatePole to the endPole
-            shift(n - 1, intermediatePole, startPole, endPole);
-        }
-    }
+            // Move n-1 discs from startPole to intermediatePole
+            shift(n - 1, startPole, endPole, intermediatePole, result);
 
-    public static void main(String[] args) {
-        System.out.print("Enter number of discs on Pole 1: ");
-        Scanner scanner = new Scanner(System.in);
-        int numberOfDiscs = scanner.nextInt(); // input of number of discs on pole 1
-        shift(numberOfDiscs, "Pole1", "Pole2", "Pole3"); // Shift function called
-        scanner.close();
+            // Add the move of the nth disc from startPole to endPole
+            result.add(String.format("Move %d from %s to %s", n, startPole, endPole));
+
+            // Move the n-1 discs from intermediatePole to endPole
+            shift(n - 1, intermediatePole, startPole, endPole, result);
+        }
     }
 }

src/main/java/com/thealgorithms/others/TowerOfHanoi.java

@@ -0,0 +1,74 @@
+package com.thealgorithms.stacks;
+
+import java.util.Set;
+import java.util.Stack;
+
+/**
+ * Evaluate a postfix (Reverse Polish) expression using a stack.
+ *
+ * <p>Example: Expression "5 6 + 2 *" results in 22.
+ * <p>Applications: Used in calculators and expression evaluation in compilers.
+ *
+ * @author Hardvan
+ */
+public final class PostfixEvaluator {
+    private PostfixEvaluator() {
+    }
+
+    private static final Set<String> OPERATORS = Set.of("+", "-", "*", "/");
+
+    /**
+     * Evaluates the given postfix expression and returns the result.
+     *
+     * @param expression The postfix expression as a string with operands and operators separated by spaces.
+     * @return The result of evaluating the postfix expression.
+     * @throws IllegalArgumentException if the expression is invalid.
+     */
+    public static int evaluatePostfix(String expression) {
+        Stack<Integer> stack = new Stack<>();
+
+        for (String token : expression.split("\\s+")) {
+            if (isOperator(token)) {
+                int operand2 = stack.pop();
+                int operand1 = stack.pop();
+                stack.push(applyOperator(token, operand1, operand2));
+            } else {
+                stack.push(Integer.valueOf(token));
+            }
+        }
+
+        if (stack.size() != 1) {
+            throw new IllegalArgumentException("Invalid expression");
+        }
+
+        return stack.pop();
+    }
+
+    /**
+     * Checks if the given token is an operator.
+     *
+     * @param token The token to check.
+     * @return true if the token is an operator, false otherwise.
+     */
+    private static boolean isOperator(String token) {
+        return OPERATORS.contains(token);
+    }
+
+    /**
+     * Applies the given operator to the two operands.
+     *
+     * @param operator The operator to apply.
+     * @param a The first operand.
+     * @param b The second operand.
+     * @return The result of applying the operator to the operands.
+     */
+    private static int applyOperator(String operator, int a, int b) {
+        return switch (operator) {
+            case "+" -> a + b;
+            case "-" -> a - b;
+            case "*" -> a * b;
+            case "/" -> a / b;
+            default -> throw new IllegalArgumentException("Invalid operator");
+        };
+    }
+}

src/main/java/com/thealgorithms/stacks/PostfixEvaluator.java

@@ -0,0 +1,76 @@
+package com.thealgorithms.stacks;
+
+import java.util.Set;
+import java.util.Stack;
+
+/**
+ * Evaluate a prefix (Polish) expression using a stack.
+ *
+ * <p>Example: Expression "+ * 2 3 4" results in 10.
+ * <p>Applications: Useful for implementing compilers and interpreters.
+ *
+ * @author Hardvan
+ */
+public final class PrefixEvaluator {
+    private PrefixEvaluator() {
+    }
+
+    private static final Set<String> OPERATORS = Set.of("+", "-", "*", "/");
+
+    /**
+     * Evaluates the given prefix expression and returns the result.
+     *
+     * @param expression The prefix expression as a string with operands and operators separated by spaces.
+     * @return The result of evaluating the prefix expression.
+     * @throws IllegalArgumentException if the expression is invalid.
+     */
+    public static int evaluatePrefix(String expression) {
+        Stack<Integer> stack = new Stack<>();
+        String[] tokens = expression.split("\\s+");
+
+        for (int i = tokens.length - 1; i >= 0; i--) {
+            String token = tokens[i];
+            if (isOperator(token)) {
+                int operand1 = stack.pop();
+                int operand2 = stack.pop();
+                stack.push(applyOperator(token, operand1, operand2));
+            } else {
+                stack.push(Integer.valueOf(token));
+            }
+        }
+
+        if (stack.size() != 1) {
+            throw new IllegalArgumentException("Invalid expression");
+        }
+
+        return stack.pop();
+    }
+
+    /**
+     * Checks if the given token is an operator.
+     *
+     * @param token The token to check.
+     * @return true if the token is an operator, false otherwise.
+     */
+    private static boolean isOperator(String token) {
+        return OPERATORS.contains(token);
+    }
+
+    /**
+     * Applies the given operator to the two operands.
+     *
+     * @param operator The operator to apply.
+     * @param a The first operand.
+     * @param b The second operand.
+     * @return The result of applying the operator to the operands.
+     */
+    private static int applyOperator(String operator, int a, int b) {
+        return switch (operator) {
+            case "+" -> a + b;
+            case "-" -> a - b;
+            case "*" -> a * b;
+            case "/" -> a / b;
+            default -> throw new IllegalArgumentException("Invalid operator");
+        };
+    }
+}