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| 1 | +/* |
| 2 | +Given the root of a binary tree, invert the tree, and return its root. |
| 3 | +
|
| 4 | +Example 1: |
| 5 | +Input: root = [4,2,7,1,3,6,9] |
| 6 | +Output: [4,7,2,9,6,3,1] |
| 7 | + */ |
| 8 | + |
| 9 | +import java.util.ArrayList; |
| 10 | +import java.util.LinkedList; |
| 11 | +import java.util.List; |
| 12 | +import java.util.Queue; |
| 13 | + |
| 14 | +public class InvertTheBinaryTree { |
| 15 | + public static void main(String[] args) { |
| 16 | + TreeNode root=new TreeNode(4); |
| 17 | + root.left=new TreeNode(2); |
| 18 | + root.right=new TreeNode(7); |
| 19 | + root.left.left=new TreeNode(1); |
| 20 | + root.left.right=new TreeNode(3); |
| 21 | + root.right.left=new TreeNode(6); |
| 22 | + root.right.right=new TreeNode(9); |
| 23 | + List<Integer> ans=invertTree(root); |
| 24 | + System.out.println(ans); |
| 25 | + } |
| 26 | + public static List<Integer> invertTree(TreeNode root) { |
| 27 | + List<Integer> result=new ArrayList<>(); |
| 28 | + if (root==null){ |
| 29 | + return result; |
| 30 | + } |
| 31 | + Queue<TreeNode> queue=new LinkedList<>(); |
| 32 | + queue.offer(root); |
| 33 | + result.add(root.data); |
| 34 | + while (!queue.isEmpty()){ |
| 35 | + int levesize= queue.size(); |
| 36 | + for (int i = 0; i < levesize; i++) { |
| 37 | + TreeNode currentnode=queue.poll(); |
| 38 | + if (currentnode.right!=null){ |
| 39 | + queue.offer(currentnode.right); |
| 40 | + result.add(currentnode.right.data); |
| 41 | + } |
| 42 | + if (currentnode.left!=null){ |
| 43 | + queue.offer(currentnode.left); |
| 44 | + result.add(currentnode.left.data); |
| 45 | + } |
| 46 | + } |
| 47 | + } |
| 48 | + return result; |
| 49 | + } |
| 50 | +} |
| 51 | +class TreeNode{ |
| 52 | + int data; |
| 53 | + TreeNode left,right; |
| 54 | + public TreeNode(int key){ |
| 55 | + key=data; |
| 56 | + left=right=null; |
| 57 | + } |
| 58 | +} |
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