solve problem Length Of Last Word

Author: P-ppc

README.md

@@ -154,6 +154,7 @@ All solutions will be accepted!
 |234|[Palindrome Linked List](https://leetcode-cn.com/problems/palindrome-linked-list/description/)|[java/py/js](./algorithms/PalindromeLinkedList)|Easy|
 |414|[Third Maximum Number](https://leetcode-cn.com/problems/third-maximum-number/description/)|[java/py/js](./algorithms/ThirdMaximumNumber)|Easy|
 |645|[Set Mismatch](https://leetcode-cn.com/problems/set-mismatch/description/)|[java/py/js](./algorithms/SetMismatch)|Easy|
+|58|[Length Of Last Word](https://leetcode-cn.com/problems/length-of-last-word/description/)|[java/py/js](./algorithms/LengthOfLastWord)|Easy|
 
 # Database
 |#|Title|Solution|Difficulty|

algorithms/LengthOfLastWord/README.md

@@ -0,0 +1,2 @@
+# Length Of Last Word
+This problem is easy to solve

algorithms/LengthOfLastWord/Solution.java

@@ -0,0 +1,19 @@
+class Solution {
+    public int lengthOfLastWord(String s) {
+        int length = 0,
+            prevLength = 0;
+        
+        for (char c : s.toCharArray()) {
+            if (c == ' ') {
+                if (length != 0) {
+                    prevLength = length;
+                }
+                length = 0;
+            } else {
+                length++;
+            }
+        }
+        
+        return length == 0 ? prevLength : length;
+    }
+}

algorithms/LengthOfLastWord/solution.js

@@ -0,0 +1,23 @@
+/**
+ * @param {string} s
+ * @return {number}
+ */
+var lengthOfLastWord = function(s) {
+    let length = 0,
+        prevLength = 0,
+        prevCharacter = null
+    
+    s.split('').forEach(c => {
+        if (c === ' ') {
+            if (length !== 0) {
+                prevLength = length
+            }
+            length = 0
+        } else if (prevCharacter !== null || prevCharacter !== ' ') {
+            length += 1
+        }
+        prevCharacter = c
+    })
+    
+    return length === 0 ? prevLength : length
+};

algorithms/LengthOfLastWord/solution.py

@@ -0,0 +1,18 @@
+class Solution(object):
+    def lengthOfLastWord(self, s):
+        """
+        :type s: str
+        :rtype: int
+        """
+        length = 0
+        prev_length = 0
+        
+        for c in s:
+            if c == ' ':
+                if length != 0:
+                    prev_length = length
+                length = 0
+            else:
+                length += 1
+        
+        return length if length != 0 else prev_length