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a4a7bb2 · Aug 4, 2018

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BinaryTreeInorderTraversal

Binary Tree Inorder Traversal

Use recursion can easy to solve this problem, like below:

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def inorderTraversal(self, root):
        """
        :type root: TreeNode
        :rtype: List[int]
        """
        # left -> root -> right
        if not root:
            return []
        return self.inorderTraversal(root.left) + [ root.val ] + self.inorderTraversal(root.right)

But we have to use iteration to solve this problem, the stack and the hashmap is the solution