Add solution #1282

Author: JoshCrozier

README.md

@@ -1,4 +1,4 @@
-# 1,395 LeetCode solutions in JavaScript
+# 1,396 LeetCode solutions in JavaScript
 
 [https://leetcodejavascript.com](https://leetcodejavascript.com)
 
@@ -974,6 +974,7 @@
 1276|[Number of Burgers with No Waste of Ingredients](./solutions/1276-number-of-burgers-with-no-waste-of-ingredients.js)|Medium|
 1277|[Count Square Submatrices with All Ones](./solutions/1277-count-square-submatrices-with-all-ones.js)|Medium|
 1278|[Palindrome Partitioning III](./solutions/1278-palindrome-partitioning-iii.js)|Hard|
+1282|[Group the People Given the Group Size They Belong To](./solutions/1282-group-the-people-given-the-group-size-they-belong-to.js)|Medium|
 1284|[Minimum Number of Flips to Convert Binary Matrix to Zero Matrix](./solutions/1284-minimum-number-of-flips-to-convert-binary-matrix-to-zero-matrix.js)|Hard|
 1286|[Iterator for Combination](./solutions/1286-iterator-for-combination.js)|Medium|
 1287|[Element Appearing More Than 25% In Sorted Array](./solutions/1287-element-appearing-more-than-25-in-sorted-array.js)|Easy|

solutions/1282-group-the-people-given-the-group-size-they-belong-to.js

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+/**
+ * 1282. Group the People Given the Group Size They Belong To
+ * https://leetcode.com/problems/group-the-people-given-the-group-size-they-belong-to/
+ * Difficulty: Medium
+ *
+ * There are n people that are split into some unknown number of groups. Each person is labeled
+ * with a unique ID from 0 to n - 1.
+ *
+ * You are given an integer array groupSizes, where groupSizes[i] is the size of the group that
+ * person i is in. For example, if groupSizes[1] = 3, then person 1 must be in a group of size 3.
+ *
+ * Return a list of groups such that each person i is in a group of size groupSizes[i].
+ *
+ * Each person should appear in exactly one group, and every person must be in a group. If there
+ * are multiple answers, return any of them. It is guaranteed that there will be at least one
+ * valid solution for the given input.
+ */
+
+/**
+ * @param {number[]} groupSizes
+ * @return {number[][]}
+ */
+var groupThePeople = function(groupSizes) {
+  const map = new Map();
+  const grouped = [];
+
+  for (let i = 0; i < groupSizes.length; i++) {
+    const size = groupSizes[i];
+
+    map.set(size, map.has(size) ? [...map.get(size), i] : [i]);
+
+    if (map.get(size).length === size) {
+      grouped.push(map.get(size));
+      map.delete(size);
+    }
+  }
+
+  return grouped;
+};