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| 1 | +/** |
| 2 | + * 1383. Maximum Performance of a Team |
| 3 | + * https://leetcode.com/problems/maximum-performance-of-a-team/ |
| 4 | + * Difficulty: Hard |
| 5 | + * |
| 6 | + * You are given two integers n and k and two integer arrays speed and efficiency both of length n. |
| 7 | + * There are n engineers numbered from 1 to n. speed[i] and efficiency[i] represent the speed and |
| 8 | + * efficiency of the ith engineer respectively. |
| 9 | + * |
| 10 | + * Choose at most k different engineers out of the n engineers to form a team with the maximum |
| 11 | + * performance. |
| 12 | + * |
| 13 | + * The performance of a team is the sum of its engineers' speeds multiplied by the minimum |
| 14 | + * efficiency among its engineers. |
| 15 | + * |
| 16 | + * Return the maximum performance of this team. Since the answer can be a huge number, return it |
| 17 | + * modulo 109 + 7. |
| 18 | + */ |
| 19 | + |
| 20 | +/** |
| 21 | + * @param {number} n |
| 22 | + * @param {number[]} speed |
| 23 | + * @param {number[]} efficiency |
| 24 | + * @param {number} k |
| 25 | + * @return {number} |
| 26 | + */ |
| 27 | +var maxPerformance = function(n, speed, efficiency, k) { |
| 28 | + const engineers = Array.from({ length: n }, (_, i) => [efficiency[i], speed[i]]) |
| 29 | + .sort((a, b) => b[0] - a[0]); |
| 30 | + const speedHeap = []; |
| 31 | + let totalSpeed = 0n; |
| 32 | + let maxPerf = 0n; |
| 33 | + const MOD = 1000000007n; |
| 34 | + |
| 35 | + function insertSpeed(val) { |
| 36 | + speedHeap.push(val); |
| 37 | + let i = speedHeap.length - 1; |
| 38 | + while (i > 0) { |
| 39 | + const parent = Math.floor((i - 1) / 2); |
| 40 | + if (speedHeap[parent] <= speedHeap[i]) break; |
| 41 | + [speedHeap[i], speedHeap[parent]] = [speedHeap[parent], speedHeap[i]]; |
| 42 | + i = parent; |
| 43 | + } |
| 44 | + } |
| 45 | + |
| 46 | + function removeMinSpeed() { |
| 47 | + const min = speedHeap[0]; |
| 48 | + speedHeap[0] = speedHeap.pop(); |
| 49 | + let i = 0; |
| 50 | + while (true) { |
| 51 | + const left = 2 * i + 1; |
| 52 | + const right = 2 * i + 2; |
| 53 | + let smallest = i; |
| 54 | + if (left < speedHeap.length && speedHeap[left] < speedHeap[smallest]) { |
| 55 | + smallest = left; |
| 56 | + } |
| 57 | + if (right < speedHeap.length && speedHeap[right] < speedHeap[smallest]) { |
| 58 | + smallest = right; |
| 59 | + } |
| 60 | + if (smallest === i) break; |
| 61 | + [speedHeap[i], speedHeap[smallest]] = [speedHeap[smallest], speedHeap[i]]; |
| 62 | + i = smallest; |
| 63 | + } |
| 64 | + return min; |
| 65 | + } |
| 66 | + |
| 67 | + for (const [eff, spd] of engineers) { |
| 68 | + insertSpeed(spd); |
| 69 | + totalSpeed += BigInt(spd); |
| 70 | + |
| 71 | + if (speedHeap.length > k) { |
| 72 | + totalSpeed -= BigInt(removeMinSpeed()); |
| 73 | + } |
| 74 | + |
| 75 | + maxPerf = maxPerf > totalSpeed * BigInt(eff) ? maxPerf : totalSpeed * BigInt(eff); |
| 76 | + } |
| 77 | + |
| 78 | + return Number(maxPerf % MOD); |
| 79 | +}; |
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