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| 1 | +/** |
| 2 | + * 210. Course Schedule II |
| 3 | + * https://leetcode.com/problems/course-schedule-ii/ |
| 4 | + * Difficulty: Medium |
| 5 | + * |
| 6 | + * There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. |
| 7 | + * You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you |
| 8 | + * must take course bi first if you want to take course ai. |
| 9 | + * |
| 10 | + * For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1. |
| 11 | + * |
| 12 | + * Return the ordering of courses you should take to finish all courses. If there are many valid |
| 13 | + * answers, return any of them. If it is impossible to finish all courses, return an empty array. |
| 14 | + */ |
| 15 | + |
| 16 | +/** |
| 17 | + * @param {number} numCourses |
| 18 | + * @param {number[][]} prerequisites |
| 19 | + * @return {number[]} |
| 20 | + */ |
| 21 | +var findOrder = function(numCourses, prerequisites) { |
| 22 | + const graph = Array(numCourses).fill().map(() => []); |
| 23 | + const seen = new Set(); |
| 24 | + const path = new Set(); |
| 25 | + const result = []; |
| 26 | + |
| 27 | + prerequisites.forEach(([c, p]) => graph[p].push(c)); |
| 28 | + |
| 29 | + for (let i = 0; i < numCourses; i++) { |
| 30 | + if (!seen.has(i) && !dfs(i)) { |
| 31 | + return []; |
| 32 | + } |
| 33 | + } |
| 34 | + |
| 35 | + return result; |
| 36 | + |
| 37 | + function dfs(course) { |
| 38 | + if (path.has(course)) return false; |
| 39 | + if (seen.has(course)) return true; |
| 40 | + |
| 41 | + path.add(course); |
| 42 | + for (const c of graph[course]) { |
| 43 | + if (!dfs(c)) { |
| 44 | + return false; |
| 45 | + } |
| 46 | + } |
| 47 | + path.delete(course); |
| 48 | + seen.add(course); |
| 49 | + result.unshift(course); |
| 50 | + return true; |
| 51 | + } |
| 52 | +}; |
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