Add solution #2637

Author: JoshCrozier

README.md

@@ -386,6 +386,7 @@
 2627|[Debounce](./2627-debounce.js)|Medium|
 2629|[Function Composition](./2629-function-composition.js)|Easy|
 2630|[Memoize II](./2630-memoize-ii.js)|Hard|
+2637|[Promise Time Limit](./2637-promise-time-limit.js)|Medium|
 2703|[Return Length of Arguments Passed](./2703-return-length-of-arguments-passed.js)|Easy|
 3110|[Score of a String](./3110-score-of-a-string.js)|Easy|
 3392|[Count Subarrays of Length Three With a Condition](./3392-count-subarrays-of-length-three-with-a-condition.js)|Easy|

solutions/2637-promise-time-limit.js

@@ -0,0 +1,28 @@
+/**
+ * 2637. Promise Time Limit
+ * https://leetcode.com/problems/promise-time-limit/
+ * Difficulty: Medium
+ *
+ * Given an asynchronous function fn and a time t in milliseconds, return a new time limited
+ * version of the input function. fn takes arguments provided to the time limited function.
+ *
+ * The time limited function should follow these rules:
+ * - If the fn completes within the time limit of t milliseconds, the time limited function
+ *   should resolve with the result.
+ * - If the execution of the fn exceeds the time limit, the time limited function should
+ *   reject with the string "Time Limit Exceeded".
+ */
+
+/**
+ * @param {Function} fn
+ * @param {number} t
+ * @return {Function}
+ */
+var timeLimit = function(fn, t) {
+  return async function(...args) {
+    return Promise.race([
+      fn(...args),
+      new Promise((_, reject) => setTimeout(() => reject('Time Limit Exceeded'), t)),
+    ]);
+  };
+};