Add solution #985

Author: JoshCrozier

solutions/0985-sum-of-even-numbers-after-queries.js

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+/**
+ * 985. Sum of Even Numbers After Queries
+ * https://leetcode.com/problems/sum-of-even-numbers-after-queries/
+ * Difficulty: Easy
+ *
+ * We have an array A of integers, and an array queries of queries.
+ *
+ * For the i-th query val = queries[i][0], index = queries[i][1],
+ * we add val to A[index].  Then, the answer to the i-th query
+ * is the sum of the even values of A.
+ *
+ * (Here, the given index = queries[i][1] is a 0-based index, and
+ * each query permanently modifies the array A.)
+ *
+ * Return the answer to all queries. Your answer array should
+ * have answer[i] as the answer to the i-th query.
+ */
+
+/**
+ * @param {number[]} A
+ * @param {number[][]} queries
+ * @return {number[]}
+ */
+var sumEvenAfterQueries = function(A, queries) {
+  return queries.reduce((sums, query) => {
+    A[query[1]] += query[0];
+    return [...sums, A.reduce((sum, n) => sum + (n % 2 === 0 ? n : 0), 0)];
+  }, []);
+};