Add solution #2725

Author: JoshCrozier

README.md

@@ -488,6 +488,7 @@
 2722|[Join Two Arrays by ID](./2722-join-two-arrays-by-id.js)|Medium|
 2723|[Add Two Promises](./2723-add-two-promises.js)|Easy|
 2724|[Sort By](./2724-sort-by.js)|Easy|
+2725|[Interval Cancellation](./2725-interval-cancellation.js)|Easy|
 2726|[Calculator with Method Chaining](./2726-calculator-with-method-chaining.js)|Easy|
 2727|[Is Object Empty](./2727-is-object-empty.js)|Easy|
 3042|[Count Prefix and Suffix Pairs I](./3042-count-prefix-and-suffix-pairs-i.js)|Easy|

solutions/2725-interval-cancellation.js

@@ -0,0 +1,26 @@
+/**
+ * 2725. Interval Cancellation
+ * https://leetcode.com/problems/interval-cancellation/
+ * Difficulty: Easy
+ *
+ * Given a function fn, an array of arguments args, and an interval time t, return a cancel
+ * function cancelFn.
+ *
+ * After a delay of cancelTimeMs, the returned cancel function cancelFn will be invoked.
+ * > setTimeout(cancelFn, cancelTimeMs)
+ *
+ * The function fn should be called with args immediately and then called again every t
+ * milliseconds until cancelFn is called at cancelTimeMs ms.
+ */
+
+/**
+ * @param {Function} fn
+ * @param {Array} args
+ * @param {number} t
+ * @return {Function}
+ */
+var cancellable = function(fn, args, t) {
+  fn(...args);
+  const timer = setInterval(() => fn(...args), t);
+  return () => clearInterval(timer);
+};