Add solution #950

Author: JoshCrozier

README.md

@@ -1,4 +1,4 @@
-# 1,034 LeetCode solutions in JavaScript
+# 1,035 LeetCode solutions in JavaScript
 
 [https://leetcode.com/](https://leetcode.com/)
 
@@ -759,6 +759,7 @@
 947|[Most Stones Removed with Same Row or Column](./solutions/0947-most-stones-removed-with-same-row-or-column.js)|Medium|
 948|[Bag of Tokens](./solutions/0948-bag-of-tokens.js)|Medium|
 949|[Largest Time for Given Digits](./solutions/0949-largest-time-for-given-digits.js)|Medium|
+950|[Reveal Cards In Increasing Order](./solutions/0950-reveal-cards-in-increasing-order.js)|Medium|
 966|[Vowel Spellchecker](./solutions/0966-vowel-spellchecker.js)|Medium|
 970|[Powerful Integers](./solutions/0970-powerful-integers.js)|Easy|
 976|[Largest Perimeter Triangle](./solutions/0976-largest-perimeter-triangle.js)|Easy|

solutions/0950-reveal-cards-in-increasing-order.js

@@ -0,0 +1,39 @@
+/**
+ * 950. Reveal Cards In Increasing Order
+ * https://leetcode.com/problems/reveal-cards-in-increasing-order/
+ * Difficulty: Medium
+ *
+ * You are given an integer array deck. There is a deck of cards where every card has a
+ * unique integer. The integer on the ith card is deck[i].
+ *
+ * You can order the deck in any order you want. Initially, all the cards start face down
+ * (unrevealed) in one deck.
+ *
+ * You will do the following steps repeatedly until all cards are revealed:
+ * 1. Take the top card of the deck, reveal it, and take it out of the deck.
+ * 2. If there are still cards in the deck then put the next top card of the deck at the
+ *    bottom of the deck.
+ * 3. If there are still unrevealed cards, go back to step 1. Otherwise, stop.
+ *
+ * Return an ordering of the deck that would reveal the cards in increasing order.
+ *
+ * Note that the first entry in the answer is considered to be the top of the deck.
+ */
+
+/**
+ * @param {number[]} deck
+ * @return {number[]}
+ */
+var deckRevealedIncreasing = function(deck) {
+  deck.sort((a, b) => b - a);
+  const result = [];
+
+  for (const card of deck) {
+    if (result.length) {
+      result.unshift(result.pop());
+    }
+    result.unshift(card);
+  }
+
+  return result;
+};