Add solution #1592

Author: JoshCrozier

README.md

@@ -1,4 +1,4 @@
-# 1,404 LeetCode solutions in JavaScript
+# 1,405 LeetCode solutions in JavaScript
 
 [https://leetcodejavascript.com](https://leetcodejavascript.com)
 
@@ -1229,6 +1229,7 @@
 1589|[Maximum Sum Obtained of Any Permutation](./solutions/1589-maximum-sum-obtained-of-any-permutation.js)|Medium|
 1590|[Make Sum Divisible by P](./solutions/1590-make-sum-divisible-by-p.js)|Medium|
 1591|[Strange Printer II](./solutions/1591-strange-printer-ii.js)|Hard|
+1592|[Rearrange Spaces Between Words](./solutions/1592-rearrange-spaces-between-words.js)|Easy|
 1598|[Crawler Log Folder](./solutions/1598-crawler-log-folder.js)|Easy|
 1657|[Determine if Two Strings Are Close](./solutions/1657-determine-if-two-strings-are-close.js)|Medium|
 1668|[Maximum Repeating Substring](./solutions/1668-maximum-repeating-substring.js)|Easy|

solutions/1592-rearrange-spaces-between-words.js

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+/**
+ * 1592. Rearrange Spaces Between Words
+ * https://leetcode.com/problems/rearrange-spaces-between-words/
+ * Difficulty: Easy
+ *
+ * You are given a string text of words that are placed among some number of spaces. Each word
+ * consists of one or more lowercase English letters and are separated by at least one space.
+ * It's guaranteed that text contains at least one word.
+ *
+ * Rearrange the spaces so that there is an equal number of spaces between every pair of adjacent
+ * words and that number is maximized. If you cannot redistribute all the spaces equally, place
+ * the extra spaces at the end, meaning the returned string should be the same length as text.
+ *
+ * Return the string after rearranging the spaces.
+ */
+
+/**
+ * @param {string} text
+ * @return {string}
+ */
+var reorderSpaces = function(text) {
+  const words = text.trim().split(/\s+/);
+  const spaceCount = text.length - words.join('').length;
+  const wordCount = words.length;
+
+  if (wordCount === 1) return words[0] + ' '.repeat(spaceCount);
+
+  const spacesBetween = Math.floor(spaceCount / (wordCount - 1));
+  const extraSpaces = spaceCount % (wordCount - 1);
+
+  return words.join(' '.repeat(spacesBetween)) + ' '.repeat(extraSpaces);
+};