Add solution #1374

Author: JoshCrozier

README.md

@@ -144,6 +144,7 @@
 1356|[Sort Integers by The Number of 1 Bits](./1356-sort-integers-by-the-number-of-1-bits.js)|Easy|
 1360|[Number of Days Between Two Dates](./1360-number-of-days-between-two-dates.js)|Easy|
 1365|[How Many Numbers Are Smaller Than the Current Number](./1365-how-many-numbers-are-smaller-than-the-current-number.js)|Easy|
+1374|[Generate a String With Characters That Have Odd Counts](./1374-generate-a-string-with-characters-that-have-odd-counts.js)|Easy|
 1380|[Lucky Numbers in a Matrix](./1380-lucky-numbers-in-a-matrix.js)|Easy|
 1472|[Design Browser History](./1472-design-browser-history.js)|Medium|
 1598|[Crawler Log Folder](./1598-crawler-log-folder.js)|Easy|

solutions/1374-generate-a-string-with-characters-that-have-odd-counts.js

@@ -0,0 +1,19 @@
+/**
+ * 1374. Generate a String With Characters That Have Odd Counts
+ * https://leetcode.com/problems/generate-a-string-with-characters-that-have-odd-counts/
+ * Difficulty: Easy
+ *
+ * Given an integer n, return a string with n characters such that each character in such
+ * string occurs an odd number of times.
+ *
+ * The returned string must contain only lowercase English letters. If there are multiples
+ * valid strings, return any of them.
+ */
+
+/**
+ * @param {number} n
+ * @return {string}
+ */
+var generateTheString = function(n) {
+  return 'a'.repeat(n % 2 ? n : n - 1) + (n % 2 ? '' : 'z');
+};