sol1.py

"""
Problem 34: https://projecteuler.net/problem=34

145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145.
Find the sum of all numbers which are equal to the sum of the factorial of their digits.
Note: As 1! = 1 and 2! = 2 are not sums they are not included.
"""

from math import factorial

DIGIT_FACTORIAL = [factorial(d) for d in range(10)]


def sum_of_digit_factorial(n: int) -> int:
    """
    Returns the sum of the factorial of digits in n
    >>> sum_of_digit_factorial(15)
    121
    >>> sum_of_digit_factorial(0)
    1
    """
    s = 0
    while n != 0:
        s += DIGIT_FACTORIAL[n % 10]
        n //= 10
    return s


def solution() -> int:
    """
    Returns the sum of all numbers whose
    sum of the factorials of all digits
    add up to the number itself.
    >>> solution()
    40730
    """
    limit = 7 * factorial(9) + 1
    return sum(i for i in range(3, limit) if sum_of_digit_factorial(i) == i)


if __name__ == "__main__":
    print(f"{solution() = }")