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refactor 314
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  • src/main/java/com/fishercoder/solutions

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src/main/java/com/fishercoder/solutions/_314.java

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@@ -9,68 +9,6 @@
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import java.util.Queue;
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import java.util.TreeMap;
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/**
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* 314. Binary Tree Vertical Order Traversal
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*
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* Given a binary tree, return the vertical order traversal of its nodes' values. (ie, from top to bottom, column by column).
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If two nodes are in the same row and column, the order should be from left to right.
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Examples:
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Given binary tree [3,9,20,null,null,15,7],
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3
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/\
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/ \
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9 20
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/\
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/ \
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15 7
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return its vertical order traversal as:
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[
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[9],
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[3,15],
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[20],
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[7]
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]
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Given binary tree [3,9,8,4,0,1,7],
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3
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/\
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/ \
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9 8
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/\ /\
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/ \/ \
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4 01 7
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return its vertical order traversal as:
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[
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[4],
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[9],
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[3,0,1],
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[8],
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[7]
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]
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Given binary tree [3,9,8,4,0,1,7,null,null,null,2,5] (0's right child is 2 and 1's left child is 5),
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3
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/\
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/ \
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9 8
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/\ /\
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/ \/ \
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4 01 7
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/\
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/ \
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5 2
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return its vertical order traversal as:
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[
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[4],
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[9,5],
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[3,0,1],
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[8,2],
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[7]
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]
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*/
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public class _314 {
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public static class Solution1 {
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public List<List<Integer>> verticalOrder(TreeNode root) {
@@ -83,7 +21,7 @@ public List<List<Integer>> verticalOrder(TreeNode root) {
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TreeMap<Integer, List<Integer>> map = new TreeMap();
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bfsQ.offer(root);
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indexQ.offer(
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0);//we set the root as index 0, left will be negative, right will be positive
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0);//we set the root as index 0, left will be negative, right will be positive
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while (!bfsQ.isEmpty()) {
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int qSize = bfsQ.size();
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for (int i = 0; i < qSize; i++) {
@@ -124,7 +62,7 @@ public List<List<Integer>> verticalOrder(TreeNode root) {
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HashMap<Integer, List<Integer>> map = new HashMap();
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bfsQ.offer(root);
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indexQ.offer(
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0);//we set the root as index 0, left will be negative, right will be positive
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0);//we set the root as index 0, left will be negative, right will be positive
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int min = 0;
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int max = 0;
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while (!bfsQ.isEmpty()) {

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